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4 years ago

If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?

Physics

2 answers:

Nastasia [14]4 years ago

7 0

Answer:

10g

Explanation:

As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".

Though melting of tin isn't a chemical change, the same logic is applied here...

Hence,

The mass of tin will be 10 g itself...

astra-53 [7]4 years ago

5 0

Answer:

10g

Explanation:

The experiment is about melting of tin. When solid tin is melted, it retains the amount of substance it originally has and we expect it to still be 10g.

Mass is the quantity or amount of matter contained in a substance. For most chemical processes, the law of conservation of matter is always succinctly observed.

The law states that "matter is neither created nor destroyed in a chemical reaction or process". Although melting is a phase change, we can adapt this law to the process. Owning to no loss of matter in the melting procedure, the amount of substance remains the same.

Therefore, we are left with about the same mass of substance we started with which is 10g.

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The drum shown in the figure has a radius of 0.40 m and a moment of inertia of 2.3 kg • m2 about an axis perpendicular to it thr

Citrus2011 [14]

The constant force applied to the rope is 7.72 N.

<h3>Net torque on the drum</h3>

The net torque on the drum is calculated as follows;

$Fr - F_fr = I \alpha$

Linear speed, v = ωr = 23 x 0.4 = 9.2 m/s

distance traveled = 14 m

<h3>Tangential acceleration</h3>

The acceleration of the drum is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

v² = 2as

a = v²/2s

a = (9.2)/2(14)

a = 0.329 m/s²

<h3>Angular acceleration of the drum</h3>

$\alpha = \frac{a}{r} = \frac{0.329}{0.4} = 0.82 \ rad/s^2$

<h3>Applied force</h3>

The constant force applied to the rope is calculated as follows;

$Fr - F_fr = I \alpha\\\\Fr = I \alpha + F_fr\\\\F = \frac{ I \alpha + F_fr}{r} \\\\F = \frac{2.3(0.82) \ + \ 3(0.4)}{0.4} \\\\F = 7.72 \ N$

Learn more about net torque here: brainly.com/question/15262027

7 0

2 years ago

What is the net force exerted by these two charges on a third charge q3 = 49.0nC placed between q1 and q2 at x3 = -1.085m ?Your

densk [106]

Answer:

The net force exerted by these two charges on a third charge is $5.468\times10^{-6}\ N$

Explanation:

Given that,

Third charge $q_{3}=49.0\ nC$

Distance $x_{3}=-1.085\ m$

Suppose The magnitude of the force F between two particles with charges Q and Q' separated by a distance d. Consider two point charges located on the x axis one charge, q₁ = -12.5 nC , is located at x₁ = -1.650 m, the second charge, q₂ = 31.5 nC , is at the origin.

We need to calculate the total force will be the vector sum of two forces

Using Coulomb's law,

$F_{13}=\dfrac{kq_{1}q_{3}}{(x_{1}-x_{3})^2}$

Put the value into the formula

$F_{13}=\dfrac{9\times10^{9}\times(-12.5\times10^{-9})\times49\times10^{-9}}{(-1.650-(-1.085))^2}$

$F_{13}=-17268.3\times10^{-9}\ N$

We need to calculate the force will be to the negative charge with opposite charges

Using Coulomb's law,

$F_{23}=\dfrac{kq_{2}q_{3}}{(x_{2}-x_{3})^2}$

Put the value into the formula

$F_{23}=\dfrac{9\times10^{9}\times(31.5\times10^{-9})\times49\times10^{-9}}{(-1.085)^2}$

$F_{23}=11800.2\times10^{-9}\ N$

The force also will be to the negative side, charges with same charge sign

We need to calculate the net force exerted by these two charges on a third charge

Using formula of net force

$F_{net}=F_{13}+F_{23}$

$F_{net}=-17268.3\times10^{-9}+11800.2\times10^{-9}$

$F_{net}=-0.0000054681\ N$

$F_{net}=-5.468\times10^{-6}\ N$

Negative sign shows the negative direction.

Hence, The net force exerted by these two charges on a third charge is $5.468\times10^{-6}\ N$

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3 years ago

What forms of rocks are produced when rocks travel to fewer stages in the cycle?

Veronika [31]

Answer:

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3 years ago

Uranium-235 has 92 protons. How many neutrons does it have?

Mrrafil [7]

Answer:

146 neutrons.

Explanation:

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4 years ago

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3 years ago

If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?​

If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?