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drek231 [11]
3 years ago
9

A solution contains a mixture of pentane and hexane at room temperature. The solution has a vapor pressure of 246 torr . Pure pe

ntane and hexane have vapor pressures of 425 torr and 151 torr, respectively, at room temperature.
a. What is the mole fraction of hexane? (Assume ideal behavior.)
Chemistry
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

X_{hexane} = 0,653

Explanation:

The pressure of the solution is:

P_{solution} = P^0_{hexane}X_{hexane} +  P^0_{pentane}X_{pentane} <em>(1)</em>

246torr = 151X_{hexane} +  425X_{pentane} <em>(1)</em>

Where X is mole fraction of each compound. Also, you can write:

1 = X_{hexane} + X_{pentane} <em>(2)</em>

Replacing (2) in (1):

246torr = 151X_{hexane} +  425(1-X_{hexane})

-179 = -274X_{hexane}

X_{hexane} = 0,653

I hope it helps!

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