True! Everything in the whole wide world is made up of matter, and the 3 types of matter are all made from atoms!!!
Even you made up of atoms :)
Answer:
Dipole-dipole attractions
Explanation:
The Cl atom is more electronegative than H, so it attracts the electrons in the H-Cl bond more to itself.
The Cl end of the molecule becomes partially negative (δ-), and the H end becomes more positive (δ+). This separation of charge is called an electric dipole,
When two HCl molecules are near each other, they arrange themselves so that the negative and positive ends of the dipoles line up and attract the two molecules together.
Answer:
The nucleus of an atom is made up of a dense ball
of <u>protons</u> and <u>neutrons</u> surrounded by <u>electrons.</u>
Explanation:
We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg . While mass of proton and neutron is 1.672623×10⁻²⁷Kg and 1.674929×10⁻²⁷ Kg respectively.
Symbol of proton= P⁺
Symbol of neutron= n⁰
The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.
You should do which candle burn the fastest colored or white
Answer:
0.67 L
Explanation:
Given data:
Volume of carbon dioxide = ?
Mass of nitroglycerine = 2.5 g
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
4C₃H₅N₃O₉ → 12CO₂ + 10 H₂O + 6N₂ + O₂
Number of moles of nitroglycerine:
Number of moles = mass/ molar mass
Number of moles = 2.4 g/ 227.1 g/mol
Number of moles = 0.01 mol
Now we will compare the moles of nitroglycerine and carbon dioxide from balance chemical equation.
C₃H₅N₃O₉ : CO₂
4 : 12
0.01 : 12/4×0.01 = 0.03 mol
Volume of CO₂:
PV = nRT
V = nRT/P
V = 0.03 mol× 0.0821 atm.L/mol.K× 273.15 K / 1 atm
V = 0.67 L
