Suppose protons were emitted rather than electrons. How would this affect the experiment?
1 answer:
Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .
The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects. We can conserve the electric energy which is equal to the qe .
The kinetic energy = 1/2
Now changing the electric potential energy into kinetic energy
v = √2qe/m
The mean velocity of proton will be less then mean velocity electron .
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Answer:
C. 7370 joules.
Explanation:
There is a mistake in the statement. Correct form is described below:
<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>
The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:
(1)
Where:
- Mass of the sample, in grams.
- Specific heat of ice, in joules per gram-degree Celsius.
- Specific heat of water, in joules per gram-degree Celsius.
- Latent heat of fusion, in joules per gram.
- Initial temperature of the sample, in degrees Celsius.
- Melting point of water, in degrees Celsius.
- Final temperature of water, in degrees Celsius.
- Total energy, in joules.
If we know that ,
,
,
,
,
and
, then the final energy to raise the temperature of the sample is:
Hence, the correct answer is C.