Suppose protons were emitted rather than electrons. How would this affect the experiment?
1 answer:
Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .
The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects. We can conserve the electric energy which is equal to the qe .
The kinetic energy = 1/2
Now changing the electric potential energy into kinetic energy
v = √2qe/m
The mean velocity of proton will be less then mean velocity electron .
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Answer:
The answer to your question is given below.
Explanation:
Potassium (K) has 19 electrons with electronic configuration of 2, 8, 8, 1.
Fluorine (F) has 9 electrons with electronic configuration of 2, 7.
Fluorine needs 1 electron to complete it's octet configuration.
Hence, potassium (K), will lose 1 electron to fluorine (F) to form potassium ion (K+) with electronic configuration of 2, 8, 8. The fluorine atom (F) will receive the 1 electron from potassium to form the fluoride ion (F-) with electronic configuration of 2, 8.
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Answer:
See explanation
Explanation:
Hello there!
In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:
Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:
And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:
I - 0 0
C - +x +x
E - x x
Which leads to the following modified equilibrium expression:
Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.
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