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2 years ago

Write a balanced chemical equation for the standard formation reaction of liquid acetic acid hch3co2.

Chemistry

1 answer:

Afina-wow [57]2 years ago

5 0

The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,

$2C(gr) +2H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.

$C(gr) +H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The balanced chemical equation for the standard formation reaction of liquid acetic acid as,

$2C(gr) +2H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The combustion of liquid acetic acid is given as,

$CH_{3} COOH(l) + 2O(g)$ → $2CO_{2}((g) +2H_{2} O(l)$ ΔH =-873

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Answer:

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Explanation:

To the above compound, we simply do the following:

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3. Identify the substituent group attached.

4. Give the substituents the lowest possible count alphabetically.

5. Combine the above to obtain the name of the compound.

Now, we shall determine the name of the compound as follow:

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2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituents group attached are:

i. Bromine (bromo), Br

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4. In counting, ene comes before yne. But in this case, ene assumes same position from either side, So we shall consider counting from the side that gives yne the lowest count. Thus, ene is at carbon 3 and yne is at carbon 1. Therefore,

i. Bromo, Br is at carbon 4.

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5. The name of the compound is:

4–bromo–5,5–dichloro–hex–3–ene–1–yne.

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