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Alex777 [14]
2 years ago
6

Write a balanced chemical equation for the standard formation reaction of liquid acetic acid hch3co2.

Chemistry
1 answer:
Afina-wow [57]2 years ago
5 0

The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,

2C(gr) +2H_{2} (g) +O_{2} (g)  → CH_{3} COOH(l)

The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.

C(gr) +H_{2} (g) +O_{2} (g) → CH_{3} COOH(l)

The balanced chemical equation for the standard formation reaction of liquid acetic acid as,

2C(gr) +2H_{2} (g) +O_{2} (g)  → CH_{3} COOH(l)

The combustion of liquid acetic acid is given as,

CH_{3} COOH(l) + 2O(g) → 2CO_{2}((g) +2H_{2} O(l)                    ΔH =-873

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_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}

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It is convenient to replace the question by an atomic symbol, _{x}^{y}\text{Z}, where <em>x </em>= the atomic number, <em>y</em> = the mass number, and Z = the symbol of the element.

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

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_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

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