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ValentinkaMS [17]
2 years ago
11

2. The following reaction takes place in a galvanic cell: 2Al(s) + 3Cu² (aq) → 2Al(aq) + 2Cu(s)

Chemistry
1 answer:
pychu [463]2 years ago
8 0

The  standard cell potential is obtained from the equation of the reaction.

<h3>What is the  standard cell potential?</h3>

The  standard cell potential is obtained from the equation of the reaction. Now we have the overall cell equation as from the half reactions as;

Oxidation half reaction;

Al(s) --->Al³+ (aq) + 3 e

Reduction half equation;

Cu²+ (aq) + 2 e →→ Cu(s)

Standard cell potential Eºcell = 0.34V - (-1.66 V) = 2 V

Now;

ΔG = -nFEcell

ΔG = -(2 * 6 * 96500 * 2)

ΔG = -2316kJ

E = 2 - 0.0592/6 log [0.0025]/[3.5 M]

E = 2 + 0.031

E = 2.031 V

Learn more about standard cell potential:brainly.com/question/14240930

#SPJ1

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Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
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Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
8.632 nm + 8.3 nm - 30.0 nm=
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Answer:

13.06800 nanometers

Explanation:

i hope you had understand !

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