50 ml of 0. 100 m hcl is titrated with 0. 1500 m naoh. the ph at the equivalence point is:_____.
1 answer:
The answer is 7.
The equivalence point of a titration is when moles of titrant added becomes equal to the moles of sample analyte.
Calculate the pH at equivalence point for a strong acid and strong base reaction.
- The given acid is HCl which is a strong acid and the base NaOH is also a strong base.
- Calculate the moles of acid HCl:
Molarity of = 0.100 M
Volume of = 50 mL = 0.050 L
×
×
- At equivalence point, same moles of base are added and thus it results into complete neutralization. Thus, all the hydrogen ions of acid are neutralized by the hydroxide ions of the base forming only water and neutral salt.
- Thus, the pH at the equivalence point becomes 7 (neutral solution).
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Explanation:
(a) It is known that relation between energy and mass is as follows.
where, E = energy
m = mass
c = speed of light = m/s
As it is given that mass is kg. So, putting the given values into the above formula as follows.
=
=
Therefore, we can conclude that the energy produced by the reaction between one electron and one positron is .
(b) When gamma ray photons are produced then they will have the same frequency. Relation between energy and frequency is as follows.
E = ..... (1)
where, h = plank's constant =
= frequency
Also, ........ (2)
Hence, equating equations (1) and (2) as follows.
=
So,
=
=
Thus, we can conclude that the frequency is .