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3 years ago

Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.

Chemistry

1 answer:

Pie3 years ago

5 0

3024.75 Joules needed to warm iron

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Sodium (chemical symbol Na) is atomic number 11 and is in the first column of the periodic table so it has one valence electron.

lisabon 2012 [21]

Na is cation so it loses electron to be positive and become stable losing one valence shells one electron so it's oxidation number is +1 ie A is correct

7 0

4 years ago

Read 2 more answers

Explain how a bond forms between sodium and chlorine in sodium chloride (NaCl).

alexandr1967 [171]

Sodium has 1 valence electron and chlorine has 7 valence electrons and the goal is to get t 8 valence electrons then they attract together, forming table salt.

6 0

3 years ago

Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate

Andrew [12]

Answer:

(2R,3S)-2-ethoxy-3-methylpentane

and

(2S,3S)-2-ethoxy-3-methylpentane

Explanation:

For this case, we will have $CH_3CH_2O^-$ as nucleophile. Also, this compound is also in excess. So, we will have as solvent $CH_3CH_2OH$ a protic solvent. Therefore the Sn1 reaction would be favored.

The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).

7 0

3 years ago

Which of the following pairs of elements belong to the same period?

bagirrra123 [75]

Answer:

He and Ar

Explanation:

3 0

3 years ago

When benzene (c6h6) reacts with bromine (br2) bromobenzene(c6h5br) is obtained: c6h6 + br2 → c6h5br + hbr what is the theoretica

saveliy_v [14]

Answer A) : We have to calculate the number of moles of Benzene involved in the reaction,

30 g / 78 moles of benzene = 0.384 moles

For bromine it will be the same process,

65 g / 159.8 moles = 0.406 moles

By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1

We need to find the mass of bromobenzene,

which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol

So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g

Hence the theoretical yield will be 60.34 g

Answer B) : To calculate the actual yield we have to divide it with theoretical yield.

(56.7g / 60.343 g ) X100% = 93.96 %

Here, we can say that we got 93.96 % of actual yield.

As we know it is impossible to get 100% yield in any reaction.

3 0

3 years ago