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aliina [53]
3 years ago
7

Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.

Chemistry
1 answer:
Pie3 years ago
5 0
3024.75 Joules needed to warm iron
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What is an example of a system in a state of balance?
Rudik [331]
For example, while the flow of fluid through a tube or electricity through a network could be in a steady state because there is a constant flow of fluid or electricity, a tank or capacitor being drained or filled with fluid is a system in transient state, because it’s volume of fluid changes with time
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3 years ago
PLEASE HELP!
svetoff [14.1K]

Answer:

period 3 and group 3

Explanation:

I'm saying group 3 because that is how I learnt it at school, but if you count it then it's in group 13.

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3 years ago
A 19.0 L helium tank is pressurized to 26.0 atm. When connected to this tank, a balloon will inflate because the pressure inside
vesna_86 [32]

Answer:

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Explanation:

Assuming Helium behaves like an ideal gas and temperature is constant.

According to Boyle's law for ideal gases, at constant temperature,

P₁V₁ = P₂V₂

P₁ = 26 atm

V₁ = 19.0 L

P₂ = 1 atm (the balloon is said to expand till the pressure matches the pressure of the atmpsphere; and the pressure of the atmosphere is 1 atm)

V₂ = ?

P₁V₁ = P₂V₂

(26 × 19) = 1 × V₂

V₂ = 494 L (it is assumed the balloon never bursts)

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Hope this Helps!!!

6 0
3 years ago
A hydrate of CuSO4 has a mass of 12.98 g before heating. After heating, the mass of the anhydrous compound is found to be 9.70 g
lukranit [14]
Explanation of the strategy: 1) calculate the mass of water and convert to number of moles, 2) convert the mass of anhydrous CuSO4 to moles, and, 3)calculate the mole ratio of water to CuSO4 anhydrous

1) Calculate the mass of water:

mass of water = mass of the hydrate CuSO4 - mass of the anhydrous compound

mass of water = 12.98 g - 9.70 g = 3.28g

2) Calculate the number of moles of water

number of moles = mass in grams / molar mass

molar mass of water = 18.01 g/mol

number of moles of water = 3.28 g / 18.01 g/mol = 0.182 mol

3) Calculate the number of moles of CuSO4 anhydrous

number of moles = mass in grams / molar mass

molar mass of Cu SO4 = 159.6 g/mol

number of moles of CuSO4 = 9.70g / 159.6 g/mol = 0.0608 moles

4) Calculate the ratio moles of water / moles of CuSO4

ratio = moles of water / moles of CuSO4 = 0.182 / 0.0608 = 2.99 ≈ 3

Therefore the molecular formula is CuSO4 . 3H2O

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