Hi, can you include the picture of the type of eclipse
Thanks :)
Answer:
Concept: Chemical Analysis
- Start by taking inventory of the elements that you have
- Make a list, one for the right side and another for the left side
- Then add coefficients to the elements to the right or left side to balance out the equation
Answer:
1.35×10¹² μg
Explanation:
Mass (Kg) = 1350 Kg
Mass (μg) =?
Thus, we can obtain the mass of the adult rhino in micrograms (μg) by converting 1350 Kg to microgram (μg) as follow:
1 Kg = 1×10⁹ μg
Therefore,
1350 Kg = 1350 kg / 1 kg × 1×10⁹ μg
1350 Kg = 1.35×10¹² μg
Therefore, 1350 Kg is equivalent to 1.35×10¹² μg.
Answer:
Average atomic mass = 63.62 amu
Explanation:
Average atomic mass is the weighted average of the individual isotopes.
And thus the weighted average =
(0.6917×63+0.3083×65)⋅amu = ?? amu.
Note that we have not accounted for the less massive copper isotopes that would decrease this mass to the accepted value of
63.55 amu.
Hope this helps! Good luck!
