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enot [183]
3 years ago
9

A rock is thrown horizontally from the top of a radio tower lands 17.0 m from the base of the tower. if the speed at which the o

bject was projected was 9.50 m/s, how high is the tower?
Physics
1 answer:
VikaD [51]3 years ago
4 0
For this problem, we use the equations derived from the projectile motion. Particularly, we use the trajectory of the projectile equation written below:

y = xtanθ + gx/2v₀²cosθ
where
y is the vertical height
x is the horizontal distance
θ is the launch angle
g is 9.81 m/s²
v₀ is the initial velocity

Since it was thrown horizontally, θ = 0°. Substituting the values,

y = 17tan0° + (9.81)(17)/2(9.50)²cos0°
y = 0.924 m
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Eva8 [605]

Answer:

C. Photosphere

Explanation:

The lights shown in the figure comes from the outermost layer of the Sun. This layer is called photosphere.

This is the layer from where the light of the Sun is radiated, before travelling through space and reaching us.

The photosphere is the coldest layer of the Sun: its surface temperature is between 4500 and 6000 K. Its width is approximately 100 km.

A characteristic of the photosphere is the presence of the sunspots, which appear as darker spots, and are regions of lower temperature caused by a concentration of magnetic flux.

3 0
3 years ago
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What can one say for sure about element #99, Einsteinium (Es))? a) There's no such element! b) It is an alkali metal. c) It is r
Dmitrij [34]

Answer:

Option (C)

Explanation:

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Thus, the correct answer is option (C).

8 0
3 years ago
What is measurements?​
Sliva [168]

Answer:

the action of measuring something.

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Two identical charges, 2 m apart, exert forces of magnitude 4 N on each other. The value of each charge is: 1. 9 × 105 C 2. 4.2
lesya692 [45]

Answer:

The value of each charge is 4.22 x 10⁻⁵ C

Explanation:

Given;

distance between the two identical charges, d = 2 m

the force of repulsion between these two charges, F = 4N

Apply Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C

Therefore, the value of each charge is 4.22 x 10⁻⁵ C

7 0
3 years ago
a circuit has a total resistance of 5 ohms and a current of 0.3 amperes. What voltage must the battery supply?
iren [92.7K]

Answer:

1.5volts

Explanation:

V=IR =0.3×5=1.5volts

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