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enot [183]
3 years ago
9

A rock is thrown horizontally from the top of a radio tower lands 17.0 m from the base of the tower. if the speed at which the o

bject was projected was 9.50 m/s, how high is the tower?
Physics
1 answer:
VikaD [51]3 years ago
4 0
For this problem, we use the equations derived from the projectile motion. Particularly, we use the trajectory of the projectile equation written below:

y = xtanθ + gx/2v₀²cosθ
where
y is the vertical height
x is the horizontal distance
θ is the launch angle
g is 9.81 m/s²
v₀ is the initial velocity

Since it was thrown horizontally, θ = 0°. Substituting the values,

y = 17tan0° + (9.81)(17)/2(9.50)²cos0°
y = 0.924 m
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Answer:

They are 7.4m apart.

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Y=Yo+Vo*t+\frac{1}{2}*a*t^2

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0=4.6-(9.81)*t^2\\t=0.68s

Because we have a contant velocity motion on X axis:

xs=vs*t\\xs=17m/s*(0.68s)\\xs=11.6m

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3 years ago
When the distance between two charges is halved, the electrical force between them?
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If the distance between two charges is halved, the electrical force between them increases by a factor 4.

In fact, the magnitude of the electric force between two charges is given by:
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We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
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the magnitude of the force changes as follows:
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