Answer:
when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium
Explanation:
The concept of center of gravity is equivalent to the concept of center of mass, in this place all external forces applied can be considered.
When we analyze the balance of a body that is the torque it is the one that defines the balance
τ = F xd
If the torque tends to restore the body to the initial position the balance is stable, but if the torque has to increase the body's rotation the balance is unstable
. When the body tends to rotate the torque with respect to the pivot point at the base it decreases because the distance from the center of gravity to the end of the base decreases in value, but it has to return it to the initial position, the balance is stable. The critical point of this process is when the center of gravity is at the limit of the body base area in this case the torque is zero; If the body rotates a little more the center of gravity is outside the base, the torque changes sign and has to increase the turn, going to an unstable balance.
In summary, when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium.
Answer:
v= 3.18 m/s
Explanation:
Given that
m= 150 g = 0.15 kg
M= 240 g = 0.24 kg
Angular speed ,ω = 150 rpm
The speed in rad/s
ω = 15.7 rad/s
The distance of center of mass from 150 g
r= 20.30 cm
The speed of the mass 150 g
v= ω r
v= 20.30 x 15.7 cm/s
v= 318.71 cm/s
v= 3.18 m/s
Answer:
it is a the answer is a btw
Explanation:
Answer:
huh,? can you explain the question more please
