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Dovator [93]
3 years ago
11

A 10 gram ball is rolling at 3 m/s. What is the energy the ball has?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

K = 0.045 J

Explanation:

It is given that,

Mass of a ball, m = 10 g = 0.01 kg

Speed of the ball, v = 3 m/s

To find,

The energy of the ball.

Solution,

Due  to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.01\times 3^2\\\\K=0.045\ J

So, the ball will have a kinetic energy of 0.045 J.

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Suppose students experiment with the tube and a variety of darts. Some darts have higher masses than others but are the same aer
san4es73 [151]

Answer:

The dart with the small mass will travel the farthest distance.

Explanation:

Acceleration is proportional to force times mass, and inertia is proportional to mass. Inertia is the reluctance of a moving body to stop, and a stationary body to start moving (inertia increses with mass). Assuming they both have the same aerodynamic design, and that they are both launched with the same force applied for the same time duration, the dart with less small mass will accelerate faster than the big mass dart. From this we can see that the small dart will have covered a longer distance before the effect of the force stops, when compared to the more massive dart.

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3 years ago
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emmainna [20.7K]
2 is sedimentary and 3 is metamorphic
7 0
2 years ago
a mass of 10kg is placed on a horizontal table with coefficient of friction is 0.5. if the mass is static, determine weight of t
zloy xaker [14]

Answer:

10

Explanation:

5 0
3 years ago
Use the following half-life graph to answer the following question:
Temka [501]

Answer:

A 1.0 min

Explanation:

The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.

From the graph in the problem, we see that the initial mass of the isotope at time t=0 is

m_0 = 50.0 g

The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:

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We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.

3 0
3 years ago
g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a
Luba_88 [7]

Answer:

  θ = 28.9

Explanation:

For this exercise let's use the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

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        sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

        sin θ₂ = 1 / 1.33 sin t 40

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        θ = sin⁻¹ 0.4833

        θ = 28.9

5 0
3 years ago
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