Question

If 30.45 grams of water is to be heated up 3.3 degrees to make baby

Answer 1

Answer:

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

$Q = mct$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

$Q = 30.45 * 4.18 * 3.3$

Q = 420.03 ≈ 420 Joules