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Elina [12.6K]
2 years ago
8

If 30.45 grams of water is to be heated up 3.3 degrees to make baby

Physics
1 answer:
KengaRu [80]2 years ago
8 0

Answer:

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

Q = 30.45 * 4.18 * 3.3

Q = 420.03 ≈ 420 Joules

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Answer:

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Explanation:

Given Data

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The component of F perpendicular to the ramp is Fy.

(a)  

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Solve for F:  

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Substitute for Fx from given data:  

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