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3 years ago

If 30.45 grams of water is to be heated up 3.3 degrees to make baby

Physics

1 answer:

KengaRu [80]3 years ago

8 0

Answer:

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

$Q = mct$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

$Q = 30.45 * 4.18 * 3.3$

Q = 420.03 ≈ 420 Joules

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2 years ago

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3 years ago

Read 2 more answers

A ball is attached to one end of a wire, the other end being fastened to the ceiling. The wire is held horizontal, and the ball

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Answer:

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Since, Air resistance is negligible, and the collision is elastic.

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