All categories

3 years ago

5.

Physics

1 answer:

lesantik [10]3 years ago

3 0

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

You might be interested in

A raft with the area A , thickness= h and the mass 600 kg, Floats in still water with 7 cm

elena55 [62]

In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.

ρwAd1g = Mg

ρwAd2g = (M + m) g

d2∕d1 = (M + m)/g

m = [(d2∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg

This means that Bubba’s mass is 120 kg.

7 0

3 years ago

A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of

disa [49]

The average acceleration is

$\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}$

5 0

3 years ago

Read 2 more answers

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If

Salsk061 [2.6K]

Complete question:

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If the switch is closed at time t = 0 s, what is the current 7.0 ms later?

Answer:

The current in the circuit 7 ms later is 0.2499 A

Explanation:

Given;

Ideal inductor, L = 45-mH

Resistor, R = 60-Ω

Ideal voltage supply, V = 15-V

Initial current at t = 0 seconds:

I₀ = V/R

I₀ = 15/60 = 0.25 A

Time constant, is given as:

T = L/R

T = (45 x 10⁻³) / (60)

T = 7.5 x 10⁻⁴ s

Change in current with respect to time, is given as;

$I(t) = I_o(1-e^{-\frac{t}{T}})$

Current in the circuit after 7 ms later:

t = 7 ms = 7 x 10⁻³ s

$I(t) = I_o(1-e^{-\frac{t}{T}})\\\\I =0.25(1-e^{-\frac{7*10^{-3}}{7.5*10^{-4}}})\\\\I = 0.25(0.9999)\\\\I = 0.2499 \ A$

Therefore, the current in the circuit 7 ms later is 0.2499 A

6 0

3 years ago

Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer

bogdanovich [222]

First sum applied the Newton's second law motion: F = ma Force = mass* acceleration This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time, force=(mass*velocity)/time such that, (mass*velocity)/time=momentum/time Therefore we get mass*velocity=momentum Momentum=mass*velocity Elephant mass=6300 kg; velocity=0.11 m/s Momentum=6300*0.11 P=693 kg (m/s) Dolphin mass=50 kg; velocity=10.4 m/s Momentum=50*10.4 P=520 kg (m/s) The elephant has more momentum(P) because it is large.

5 0

3 years ago

Determine the magnitude of the force F1F1 component acting along the uu axis. Express your answer to three significant figures a

dybincka [34]

The first image below shows force F1 and the axes.

Answer: $(F_{1})_{u}=$ 3.62 kN