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Olenka [21]
3 years ago
15

5.

Physics
1 answer:
lesantik [10]3 years ago
3 0

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

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A raft with the area A , thickness= h and the mass 600 kg, Floats in still water with 7 cm
elena55 [62]

<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.

<span>ρwAd1g = Mg</span>

ρw<span>Ad2g = (M + m) g</span>

<span>d2∕d1 = (M + m)/g</span>

m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>

This means that Bubba’s mass is 120 kg.

7 0
3 years ago
A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of
disa [49]

The average acceleration is

\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}

5 0
3 years ago
Read 2 more answers
A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If
Salsk061 [2.6K]

Complete question:

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If the switch is closed at time t = 0 s, what is the current 7.0 ms later?

Answer:

The current in the circuit 7 ms later is 0.2499 A

Explanation:

Given;

Ideal inductor, L = 45-mH

Resistor, R =  60-Ω

Ideal voltage supply, V = 15-V

Initial current at t = 0 seconds:

I₀ = V/R

I₀  = 15/60 = 0.25 A

Time constant, is given as:

T = L/R

T = (45 x 10⁻³) / (60)

T = 7.5 x 10⁻⁴ s

Change in current with respect to time, is given as;

I(t) = I_o(1-e^{-\frac{t}{T}})

Current in the circuit after 7 ms later:

t = 7 ms = 7 x 10⁻³ s

I(t) = I_o(1-e^{-\frac{t}{T}})\\\\I =0.25(1-e^{-\frac{7*10^{-3}}{7.5*10^{-4}}})\\\\I = 0.25(0.9999)\\\\I = 0.2499 \ A

Therefore, the current in the circuit 7 ms later is 0.2499 A

6 0
3 years ago
Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
bogdanovich [222]
<span>First sum applied the Newton's second law motion: F = ma Force = mass* acceleration This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time, force=(mass*velocity)/time such that, (mass*velocity)/time=momentum/time Therefore we get mass*velocity=momentum Momentum=mass*velocity Elephant mass=6300 kg; velocity=0.11 m/s Momentum=6300*0.11 P=693 kg (m/s) Dolphin mass=50 kg; velocity=10.4 m/s Momentum=50*10.4 P=520 kg (m/s) The elephant has more momentum(P) because it is large.</span>
5 0
3 years ago
Determine the magnitude of the force F1F1 component acting along the uu axis. Express your answer to three significant figures a
dybincka [34]

The first image below shows force F1 and the axes.

Answer: (F_{1})_{u}= 3.62 kN

Explanation: The second figure below express the parallelogram method to calculate the u component of force F1.

The <u>Parallelogram</u> <u>Method</u> is a method to determine resultant force and is applied as described in the question above.

With the three components, F_{1},(F_{1})_{u} and (F_{1})_{v} and angles, it can be used the <u>Law</u> <u>of</u> <u>Sines</u>, which states:

\frac{a}{sin\alpha} =\frac{b}{sin\beta} =\frac{c}{sin\theta}

i.e., there is a relation of proportionality between an angle and its opposite side.

For the triangle below:

\frac{u}{sin30} =\frac{F_{1}}{sin105}

u=F_{1}\frac{sin(30)}{sin(105)}

u=7\frac{0.5}{0.966}

u = 3.62

The magnitude of the component acting along the u-axis is 3.62kN.

5 0
3 years ago
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