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Zielflug [23.3K]
3 years ago
13

A gas laser has a cavity length of 1/3 m and a single oscillation frequency of 9.0 x 1014 Hz. What is the cavity mode number?

Physics
1 answer:
Eddi Din [679]3 years ago
5 0

Answer:

2 × 10⁶

Explanation:

Data provided in the question:

Cavity length, L = \frac{1}{3}m

Oscillation frequency, f_m = 9.0 × 10¹⁴ Hz

Now,

we know,

f_m=\frac{c}{\lambda_m}

here,

c is the speed of light = 3 × 10⁸ m/s

\lambda_m = Wavelength of mode m inside the laser cavity

m is the cavity mode number

Thus,

9.0\times10^{14}=\frac{3\times10^8}{\lambda_m}

or

\lambda_m = \frac{1}{3} × 10⁻⁶

Also,

m\lambda_m = 2L

Therefore,

m × \frac{1}{3} × 10⁻⁶ = 2 × \frac{1}{3}

or

m = 2 × 10⁶

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lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

Therefore, the new weight is

F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

F'=\frac{640}{16}=40 N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
Why does a balloon that is rubbed on someoneâs shirt stick to a wall at a party?
alukav5142 [94]
When we rub balloon on a shirt the balloon will steal electrons from the shirt and the shirt will become positively charged and balloon will negatively charged.<span>The reason that the balloon will stick to the wall is because the negative charges in the balloon will make the electrons in the wall move to the other side of their atoms and this leaves the surface of the wall positively charged.</span>
8 0
3 years ago
The magnitude of the velocity vector of the car is ∣∣v→∣∣ = 78 ft/s. If the vector v→ forms an angle θ = 0.09 rad with the horiz
kotegsom [21]

Answer:

\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

Explanation:

The x- and y- components of the velocity vector can be written as following:

\vec{v}_x = ||\vec{v}||\cos(\theta)\^i

\vec{v}_y = ||\vec{v}||\sin(\theta)\^j

Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

\vec{v} = 78\cos(0.09)\^i + 78\sin(0.09)\^j\\\vec{v} = (77.68~{\rm ft/s})\^i + (7.01~{\rm ft/s})\^j

3 0
3 years ago
16. Evaluate the expression below if<br> a = -8, b = 17, and c = 21<br> az - (b + c)
IceJOKER [234]
Do u have to find z? how do yk what z is?
4 0
3 years ago
Read 2 more answers
In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,
Anon25 [30]

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

F=\dfrac{dP}{dt}

Therefore force F

F=\dfrac{\Delta P}{\Delta t}

F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N

F=4040.81 N

Therefore force on the ball will be 4040.81 N

6 0
3 years ago
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