Answer:
The given grammar is :
S = T V ;
V = C X
X = , V | ε
T = float | double
C = z | w
1.
Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.
From the given grammar,
Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.
No other variables generate variable X or ε.
So, only variable X is nullable.
2.
First of nullable variable X is First (X ) = , and ε (epsilon).
L.H.S.
The first of other varibles are :
First (S) = {float, double }
First (T) = {float, double }
First (V) = {z, w}
First (C) = {z, w}
R.H.S.
First (T V ; ) = {float, double }
First ( C X ) = {z, w}
First (, V) = ,
First ( ε ) = ε
First (float) = float
First (double) = double
First (z) = z
First (w) = w
Explanation:
Answer:
Springs store energy when compressed and release energy when they rebound
Explanation:
Answer:
a) 0.697*10³ lb.in
b) 6.352 ksi
Explanation:
a)
For cylinder AB:
Let Length of AB = 12 in
![c=\frac{1}{2}d=\frac{1}{2} *1.1=0.55in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}0.55^4=0.1437\ in^4\\](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B2%7Dd%3D%5Cfrac%7B1%7D%7B2%7D%20%2A1.1%3D0.55in%5C%5C%20J%3D%5Cfrac%7B%5Cpi%20c%5E4%7D%7B2%7D%3D%5Cfrac%7B%5Cpi%7D%7B2%7D0.55%5E4%3D0.1437%5C%20in%5E4%5C%5C)
![\phi_B=\frac{T_{AB}L}{GJ}=\frac{T_{AB}*12}{3.3*10^6*0.1437} =2.53*10^{-5}T_{AB}](https://tex.z-dn.net/?f=%5Cphi_B%3D%5Cfrac%7BT_%7BAB%7DL%7D%7BGJ%7D%3D%5Cfrac%7BT_%7BAB%7D%2A12%7D%7B3.3%2A10%5E6%2A0.1437%7D%20%20%3D2.53%2A10%5E%7B-5%7DT_%7BAB%7D)
For cylinder BC:
Let Length of BC = 18 in
![c=\frac{1}{2}d=\frac{1}{2} *2.2=1.1in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}1.1^4=2.2998\ in^4\\](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B2%7Dd%3D%5Cfrac%7B1%7D%7B2%7D%20%2A2.2%3D1.1in%5C%5C%20J%3D%5Cfrac%7B%5Cpi%20c%5E4%7D%7B2%7D%3D%5Cfrac%7B%5Cpi%7D%7B2%7D1.1%5E4%3D2.2998%5C%20in%5E4%5C%5C)
![\phi_B=\frac{T_{BC}L}{GJ}=\frac{T_{BC}*18}{5.9*10^6*2.2998} =1.3266*10^{-6}T_{BC}](https://tex.z-dn.net/?f=%5Cphi_B%3D%5Cfrac%7BT_%7BBC%7DL%7D%7BGJ%7D%3D%5Cfrac%7BT_%7BBC%7D%2A18%7D%7B5.9%2A10%5E6%2A2.2998%7D%20%20%3D1.3266%2A10%5E%7B-6%7DT_%7BBC%7D)
![2.53*10^{-5}T_{AB}=1.3266*10^{-6}T_{BC}\\T_{BC}=19.0717T_{AB}](https://tex.z-dn.net/?f=2.53%2A10%5E%7B-5%7DT_%7BAB%7D%3D1.3266%2A10%5E%7B-6%7DT_%7BBC%7D%5C%5CT_%7BBC%7D%3D19.0717T_%7BAB%7D)
![T_{AB}+T_{BC}-T=0\\T_{AB}+T_{BC}=T\\T_{AB}+T_{BC}=14*10^3\ lb.in\\but\ T_{BC}=19.0717T_{AB}\\T_{AB}+19.0717T_{AB}=14*10^3\\20.0717T_{AB}=14*10^3\\T_{AB}=0.697*10^3\ lb.in\\T_{BC}=13.302*10^3\ lb.in](https://tex.z-dn.net/?f=T_%7BAB%7D%2BT_%7BBC%7D-T%3D0%5C%5CT_%7BAB%7D%2BT_%7BBC%7D%3DT%5C%5CT_%7BAB%7D%2BT_%7BBC%7D%3D14%2A10%5E3%5C%20lb.in%5C%5Cbut%5C%20T_%7BBC%7D%3D19.0717T_%7BAB%7D%5C%5CT_%7BAB%7D%2B19.0717T_%7BAB%7D%3D14%2A10%5E3%5C%5C20.0717T_%7BAB%7D%3D14%2A10%5E3%5C%5CT_%7BAB%7D%3D0.697%2A10%5E3%5C%20lb.in%5C%5CT_%7BBC%7D%3D13.302%2A10%5E3%5C%20lb.in)
b) Maximum shear stress in BC
![\tau_{BC}=\frac{T_{BC}}{J}c=13.302*10^3*1.1/2.2998=6.352\ ksi](https://tex.z-dn.net/?f=%5Ctau_%7BBC%7D%3D%5Cfrac%7BT_%7BBC%7D%7D%7BJ%7Dc%3D13.302%2A10%5E3%2A1.1%2F2.2998%3D6.352%5C%20ksi)
Maximum shear stress in AB
![\tau_{AB}=\frac{T_{AB}}{J}c=0.697*10^3*0.55/0.1437=2.667\ ksi](https://tex.z-dn.net/?f=%5Ctau_%7BAB%7D%3D%5Cfrac%7BT_%7BAB%7D%7D%7BJ%7Dc%3D0.697%2A10%5E3%2A0.55%2F0.1437%3D2.667%5C%20ksi)
The answer is choice C
Explanation:
As during construction ,the site is cleared for all debris before laying out the foundation. Even the sewer lines are dug out .
So it will be useful for the construction crews to connect the pipes to the sewer lines before the foundation is poured.
But usually the steps take in construction activity is:- first the site is cleared for the foundation to be poured and once the foundation wall is set , then all utilities , including plumbing and electrical activities are done.,
After this process is over, the city inspector comes to check whether the foundation has been laid down as per the code of construction.
Only after that the rest of the construction activity follows through.