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DaniilM [7]
3 years ago
13

Which equation is used to calculate the magnetic force on a charge moving in a magnetic field?

Physics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

B

Explanation:

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Suppose a large housefly 3.0 m away from you makes sound with an intensity level of 40.0 dB. What would be the sound intensity l
melisa1 [442]

Answer:

Explanation:

Let the intensity of the noise be represented by I

Given that

40dB = 10 log 10 ⁡ ( I /I•) ........ 1

I• is the lowest or threshold intensity of sound made.

I represents the intensity of the sound/ noise

The intensity of noise of 1000flies will be

β = 10 log 10 ⁡(1000I/I•)

Open up the bracket

β = 10 log 10(1000)+ 10 log 10(I/I•)

10 log 10(10^3)+10 log 10(I/I•)

3×10(10 log 10) +10 log 10(I/I•)

Recall, 10 log 10 = 1

30×1 + 10 log 10(I/I•).........2

Put equation 1 into 2

β =30+40

= 70db

5 0
3 years ago
3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through
True [87]

Answer:

e) 179 J

Explanation:

E_{o} = Magnitude of electric field = 5 V/m

A = Area of window = 1.5 m²

c = speed of electromagnetic wave = 3 x 10⁸ m/s

\Delta t = time interval = 1 h = 3600 sec

radiation energy is given as

U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t

U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)

U = 179 J

6 0
3 years ago
0.054x2.33x90............
guapka [62]
<h2>0.054×2.33×90</h2><h3>=0.11582×90</h3><h3>=11.3238</h3>

please mark this answer as brainlist

5 0
2 years ago
Derive an expression for the energy needed to launch an object from the surface of Earth to a height h above the surface.Ignorin
Sergio [31]

Answer:

Explanation:

Potential energy on the surface of the earth

= - GMm/ R

Potential at height h

=  - GMm/ (R+h)

Potential difference

= GMm/ R -  GMm/ (R+h)

= GMm ( 1/R - 1/ R+h )

= GMmh / R (R +h)

This will be the energy needed  to launch an object from the surface of Earth to a height h above the surface.

Extra  energy is needed to get the same object into orbit at height h

= Kinetic energy of the orbiting object at height h

= 1/2 x potential energy at height h

= 1/2 x GMm / ( R + h)

8 0
3 years ago
How do you calculate elastic potential energy
Nimfa-mama [501]
U=1/2kx2

This image sums it up
5 0
3 years ago
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