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zhenek [66]
2 years ago
14

Why is there a need for soil engineering?

Engineering
1 answer:
Anvisha [2.4K]2 years ago
6 0

Answer:

Soil engineering helps in analyzing the structure and composition of the soil of the proposed construction site, thus helping in deciding whether the soil of the proposed construction site or building is worth exploiting.

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Air enters the compressor of an ideal gas refrigeration cycle at 7∘C and 35 kPa and the turbine at 37∘C and 160 kPa. The mass fl
amid [387]

It appears that your answer contains either a link or inappropriate words. Please correct and submit again! error

Had to screenshot the solution check attached

5 0
4 years ago
The substance called olivine may have any composition between Mg2SiO4 and Fe2SiO4, i.e. the Mg atoms can be replaced by Fe atoms
Ipatiy [6.2K]

Answer:

The answer is "0.147 nm and  99.63 mol %"

Explanation:

In point (a):

\to nk1 = 062

\to \text{Bragg angle} \theta =37.21^{\circ}

\to \text{diffraction angle} 2 \theta = 74.42^{\circ}

\to \lambda = 0.1790 nm

find:

d(062)=?

formula:

\to nx = 2d \sin  \theta

\to  d(062) = \frac{1 \times 0.1790^{\circ}}{2 \times \sin 37.21^{\circ}}\\

               = \frac{0.1790^{\circ}}{2 \times 0.604738126}\\\\= \frac{0.29599589}{2}\\\\= 0.147 \\

In point (b):

\to Mg_2SiO_4\longleftrightarrow  Fe_2SiO_4

d= 0.14774  \ \ \ \ \ olivine = 0.147 \ \ \ \  \ 0.15153

formula:

\to d=\frac{a}{\sqrt{n^2+k^2+i^2}}\\

that's why the composition value equal to 99.63 %

3 0
3 years ago
If a mineral fractures, how many directions of cleavage does it have?
Sveta_85 [38]

Answer:

Cleavage occurs in straight lines in a mineral, with different minerals exhibiting 1, 2, or 3 directions of cleavage. Fractures however are irregular and follow how specific pattern or cleavages

3 0
3 years ago
Read 2 more answers
In the truss below, the vertical reaction force at A is
Montano1993 [528]
It’s c trust just trust
7 0
3 years ago
A closed, 0.4-m-diameter cylindrical tank is completely filled with oil (SG 0.9)and rotates about its vertical longitudinal axis
egoroff_w [7]

Answer: p_{B} - p_{A} = 28800 Pa or 28.8 kPa

Explanation: To determine the pressure of a liquid in a rotating tank,it is used:

p = \frac{p_{fluid}.w^{2}.r^{2} }{2} - γfluid . z + c

where:

p_{fluid} is the liquid's density

w is the angular velocity

r is the radius

γfluid.z is the pressure variation due to centrifugal force.

For this question, the difference between a point on the circumference and a point on the axis will be:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}.r_{B} ^{2} }{2} - γfluid.z_{B} - (\frac{p_{fluid}.w^{2}.r_{A} ^{2} }{2} - γfluid.z_{A})

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} ) - γfluid(z_{B} -z_{A})

Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} )

p_{B} - p_{A} = \frac{0.9.10^3.40^2}{2}(0.2^2 - 0)

p_{B} - p_{A} = 28800

The difference in pressure between two points, one on the circumference and the other on the axis is p_{B} - p_{A} = 28800 Pa or 28.8 kPa

8 0
3 years ago
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