Answer:
correct option is (A) 0.5
Explanation:
given data
axial column load = 250 kN per meter
footing placed = 0.5 m
cohesion = 25 kPa
internal friction angle = 5°
solution
we know angle of internal friction is 5° that is near to 0°
so it means the soil is almost cohesive soil.
and for a pure cohesive soil
= 0
and we know formula for
is
= (Nq - 1 ) × tan(Ф) ..................1
so here Ф is very less
should be nearest to zero
and its value can be 0.5
so correct option is (A) 0.5
Answer:
12ma²
Explanation:
The moment of inertia I = ∑mr² where m = mass and r = distance from shaft
Since we have three masses,
So, I = m₁r₁² + m₂r₂² + m₃r₃² where m₁ = first mass = m, m₂ = second mass = 3m and m₃ = third mass = 2m. Also, r₁ = distance of first mass from shaft = a, r₂ = distance of second mass from shaft = a and r₃ = distance of third mass from shaft = 2a.
I = m₁r₁² + m₂r₂² + m₃r₃²
I = ma² + 3ma² + 2m(2a)²
I = ma² + 3ma² + 2m(4a²)
I = ma² + 3ma² + 8ma²
I = 12ma²
Answer:
The answer which is a calculation can be found as an attached document
Explanation:
Answer:
-10.83m
Explanation:
Please see the attachment