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muminat
1 year ago
12

when he returns his hertz rent-a-rocket after one week's cruising in the galaxy, spock is shocked to be billed for three weeks'

rental. assuming that he traveled straight out and then straight back, always at the same speed, how fast was he traveling?
Physics
1 answer:
Flura [38]1 year ago
4 0

Mr. spoke is travelling with speed v = 9.4c.

Mr. spoke is apparently unknowing of  theory of special relativity by Einstein. The theory states that moving clock tick slower than stationery clock.

Time elapse =∆t = 3 weeks

(In earth stationery frame)

Time ellipse= ∆t' = 1 week

(In the frame of rocket)

∆t' = ∆t'/γ

1/y² = 1 - v²/c²

∆t'²/∆t² =

=1²/3²

=1/9

c= 3×10⁸m/s

on solving above equation we get :

v = 9.4c

He was spreading around at close to the speed of light.

Experience significant time dilatation.

He is travelling with speed  v = 9.4c.

To know more about special theory of relativity :

brainly.com/question/28289663

# SPJ4

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How is velocity different from speed?
enyata [817]

Velocity, unlike speed, includes a direction.

Velocity is a vector quantity which is defined by magnitude and direction.

Speed is a scalar quantity. It is the rate at which an object moves regardless of which direction.

5 0
3 years ago
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A stone of mass 150g is rotated in a horizontal circle at 10m/s which is attached to the end of a 1m long. what will be the acce
erastova [34]

force is mass multiply by acceleration so it will be 150 multiply by 10 is 1500N

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2 years ago
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g A change in the initial _____ of a projectile changes the range and maximum height of the projectile.​
docker41 [41]

Answer:

Velocity.

Explanation:

Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.

As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:

Horizontal range: As per expression:

R= (u^{2}*sin2θ)/g

the range depending on the square of the initial velocity.

Maximum height: As per expression:

H= (u^{2} * sin^{2}θ )/2g

the maximum distance also depends upon square of the initial velocity.

​

​

​

7 0
3 years ago
A bobsled has a momentum of 4000 kg•m/s to the south. Friction on the
mina [271]

Answer:

1500 north

Explanation:

8 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
givi [52]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

f = f_0 (\frac{v_0}{v_0-v})

Here,

f_0 = Frequency of Source

v_s = Speed of sound

f = Frequency heard before slowing down

f' = Frequency heard after slowing down

v  = Speed of the train before slowing down

So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,

The first equation is,

f = f_0 (\frac{v_0}{v_0-v})

300 = f_0 (\frac{343}{343-v})

(300*343) - 300v = 343f_0

Now the second expression will be,

f' = f_0 (\frac{v_0}{v_0-v/2})

290 = (343)(\frac{v_0}{343-v/2})

290*343-145v = 343f_0

Dividing the two expression we have,

\frac{(300*343) - 300v}{290*343-145v} = 1

Solving for v, we have,

v = 22.12m/s

Therefore the speed of the train before and after slowing down is 22.12m/s

6 0
3 years ago
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