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Elden [556K]
2 years ago
9

When driving your car forward, your car's wheels are spinning. What is the direction of rotation of your car's wheels

Physics
1 answer:
Maurinko [17]2 years ago
7 0

The rotation axes of a car's wheels are horizontal and perpendicular to the direction of movement when the vehicle is moving ahead. The "direction" of the wheels' rotation, or more precisely, the direction of the angular velocity vector, is then uniquely specified by a mathematical convention.

<h3>Explain the rotation of the car's wheels and its direction?</h3>

In other words, it is impossible to say whether an object is rotating clockwise or counterclockwise without also mentioning the angle from which the object is being viewed. The wheels would be said to be turning clockwise if the car passed you from left to right. However, someone on the opposite side of the street would claim that they were rotating the opposite way. However, both observers would concur on the definition of the angular velocity vector's direction.

<h3>What is angular velocity and axis of rotation?</h3>

The symbol ω represents the magnitude of the angular velocity, which is equal to 2π divided by the duration of one rotation. In other words, ω = 2π / T. But what is important is the vector's orientation. And to do that, we employ the aforementioned "Right Hand Rule." Your right hand should be held with the thumb pointing in the direction of the rotation vector and the fingers curled in the direction the wheel turns.

In order to specify the angular velocity of each component that makes up the wheel with respect to the axis of rotation, a more formal definition uses a vector cross-product.

To know more about angular velocity visit:
brainly.com/question/14611467

#SPJ4

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a 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system.
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Explanation:It is given that,

Mass of bumper car, m₁ = 202 kg

Initial speed of the bumper car, u₁ = 8.5 m/s

Mass of the other car, m₂ = 355 kg

Initial velocity of the other car is 0 as it at rest, u₂ = 0

Final velocity of the other car after collision, v₂ = 5.8 m/s

Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁

Using the conservation of linear momentum as :

p₁ = m₁v₁ = -342 kg-m/s

So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.

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Review. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00 mT . The angular momen
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The speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

The angular momentum(L) of an electron moving in a circular path is given by the formula,

L = mvr ........(i)

We know that the radius of the path of an electron in a magnetic field is

r = mv/qB

Putting this value in equation (i),

L = mv x mv/qB

or L = (mv)^2/qB

Putting the given values in the above equation,

4 x 10^-25 = (9.1x10^-31)^2 x v^2/ 1.6 x 10^-19 x 1 x 10^-3

v comes out to be 8.88 x 10^7 m/s.

Hence, the speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

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