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2 years ago

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A 2. 00 g sample of cocl2. x h2o is dried in an oven. when the anhydrous salt is removed from the oven, its mass is 1. 565 g. wh

at is the value of x?

1 answer:

timofeeve [1]2 years ago

3 0

It is Cobalt(II)chloride dihydrate. The value of x is 2.

First, we have to determine the mass of H₂O that was evaporated upon heating which will be = 2.00g - 1.56 g

= 0.435 g

So,

CoCl₂ + x.H₂O → CoCl₂.xH₂O

Molecular mass of CoCl₂ = 129.839 g/mol

Molecular mass of H₂O = 18 g/mol

Weight of sample after heating = 1.565 g

Weight of H₂O evaporated = 0.435 g

Hence,

$18x = \frac{129.839X0.435}{1.565} \\x = \frac{55.48}{28.17} \\x = 1.9$

x ≈ 2

So, it is Cobalt(II)chloride dihydrate.

Learn more about molecular mass here:

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A popular car has a gas tank that holds a maximum of 14.5 gallons of fuel. What is

gulaghasi [49]

Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

$D=\frac{CxB}{A}$

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

$D=\frac{14.5 gallonsx3.785 liters}{1 gallon}$

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

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2 years ago

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A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and

sammy [17]

<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(S_8)$ = 0.800 g

$M_{solute}$ = Molar mass of solute $(S-8)$ = 256.52 g/mol

$W_{solvent}$ = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m$

<u>Calculation for freezing point of solution:</u>

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

or,

$\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm$

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC$

Hence, the freezing point of solution is 16.5°C

<u>Calculation for boiling point of solution:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

or,

$\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm$

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC$

Hence, the boiling point of solution is 118.2°C

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3 years ago

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alexdok [17]

I’m don’t kill me if I’m wrong but I think it’s high melting point

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3 years ago

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2. What is the mass of a car with a momentum of 10,000.00 kgm/s, traveling at 15.0 m/s?

Svetradugi [14.3K]

Answer:

666.67 kg is the mass of a car.

Explanation:

Momentum is defined as amount of motion possessed by the the moving body. It is mathematically calculated by multiplying mass into velocity by which object is moving.

$Momentum(P)=Mass(m)\times Velocity(v)$

Mass of the car = m =?

Velocity of the car = v = 15.0 m/s

Momentum of the car = P = 10,000.00 kgm/s

$m=\frac{P}{v}$

$m=\frac{ 10,000.00 kgm/s}{15.0 m/s}=666.67 kg$

666.67 kg is the mass of a car.

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3 years ago

28 grams of Al react with 30 Oxygen gas (O2) to produce Al Oxide (Al2O3). How many grams of Al Oxide will be produced

Kamila [148]

Answer:

58

Explanation:

Due to conservation of energy, the sum of the reactants = the sum of the products. So 28 + 30 = 58g

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