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ra1l [238]
2 years ago
8

If a 22. 5 mm copper (ii) solution(solution a) had an absorbance of 1. 65. what would be the absorbance if 8 ml of solution a wa

s used to prepare a 20. 0 ml of a new copper (ii) solution?
Chemistry
1 answer:
Andru [333]2 years ago
3 0

If a 22. 5 mm copper (ii) solution(solution a) had an absorbance of 1. 65. Then, the absorbance if 8 ml of solution a was used to prepare a 20. 0 ml of a new copper (ii) solution is 918.84.

According to Beer-Lambert law, the absorbance (A) of a substance depends on its concentration (c)

A = ε . l. c

where,

ε: absorptivity of the species

l: optical path length

A 22.5 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . l . c

1.65 = ε . l . 22.5 mM

ε . l  = 37.125 mM⁻¹

We will calculate the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

22.5mM . 8 mL = C₂ . 20.0 mL

C₂ = 24.75 mM

The absorbance of the second solution is:

A = (ε . l ). c

A = (37.125 mM⁻¹) x 24.75 mM = 918.84

Thus, we find that the value of absorbance is 918.84.

Learn more about absorption:

brainly.com/question/23938376

#SPJ4

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