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Pepsi [2]
3 years ago
6

Two iron weights, one twice the mass of the other, are dropped from the top of a building. Compared with the lighter weight, the

twice as heavy weight will hit the ground with...
Physics
2 answers:
OverLord2011 [107]3 years ago
8 0
The same acceleration, the same speed, at the same time, with double the momentum, the same potential energy, and double the kinetic energy.
Whitepunk [10]3 years ago
4 0
The twice as heavy weight will hit the ground with more force, or impact.
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A kangaroo hops at an angle of 25° to the horizontal with a velocity of 20 m/s. What is the vertical component of the velocity?
sp2606 [1]

Answer:

A. 8.5 m/s

Explanation:

vᵧ = v sin θ

vᵧ = (20 m/s) (sin 25°)

vᵧ = 8.5 m/s

6 0
3 years ago
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Five multiple choice science questions! Help please!
andreyandreev [35.5K]
1) the sun (greek name Helios gives heliocentric)
2) A.  Newton's laws of motion can prove this as well as Kepler's Laws
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5) B (International Space Station gives a hint)

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4 years ago
Which of the following is not a good approximation of the relationship between independent and dependent variables? A. independe
KengaRu [80]

c would be the right answer for this problem

7 0
4 years ago
What is the heat transfer mechanism responsible for the daily wind cycle
Mashcka [7]
<span>heat transfer though convection</span>
4 0
3 years ago
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Two tiny conducting spheres are identical and carry charges of -20μC and +50μC. They are separeted by a distance of 2.50cm. (a)
Dahasolnce [82]

Answer:

14400\ \text{N}, Attractive

3240\ \text{N}, Repulsive

Explanation:

q_1 = -20 μC

q_2 = 50 μC

r = Distance between the charges = 2.5 cm

k = Coulomb constant = 9\times 10^9\ \text{Nm}^2/\text{C}^2

Electrical force is given by

F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (-20\times 10^{-6})\times (50\times 10^{-6})}{(2.5\times10^{-2})^2}\\\Rightarrow F=-14400\ \text{N}

The magnitude of force each sphere will experience is 14400\ \text{N}

Since the charges have opposite charges they will attract each other.

Now the charges are brought into contact with each other so the resultant charge will be

q=\dfrac{q_1+q_2}{2}\\\Rightarrow q=\dfrac{-20+50}{2}\\\Rightarrow q=15\ \mu\text{C}

F=\dfrac{kq^2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (15\times 10^{-6})^2}{(2.5\times 10^{-2})^2}\\\Rightarrow F=3240\ \text{N}

The magntude of the force the spheres experience will be 3240\ \text{N}

The spheres have the same charge now so they will repel each other.

7 0
3 years ago
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