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tiny-mole [99]
3 years ago
14

A 66 kg person is parachuting and experiencing a downward acceleration of 2.1 m/s2. The mass of the parachute is 4.0 kg. (a) Wha

t is the upward force on the open parachute from the air?
Physics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

539N

Explanation:

Parameters given:

Mass of person = 66kg

Mass of parachute = 4kg

Downward acceleration = 2.1 m/s²

The total force acting on the system is the sum of the force of gravity and the force due to air acting opposite gravity:

F = mg - F(a)

Where g = acceleration due to gravity

Force is given as:

F = ma

=> ma = mg - F(a)

=> F(a) = mg - ma

F(a) = m(g - a)

m is the mass of the entire sustem

m = 66 + 4 = 70kg

=> F(a) = 70(9.8 - 2.1)

F(a) = 70 * 7.7

F(a) = 539N

The upward force on the open parachute from the air is 539N

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Answer:

Q = 836.4 Joules.

Explanation:

Given the following data;

Mass = 100 grams

Initial temperature = 25°C

Final temperature = 45°C

We know that the specific heat capacity of water is equal to 4.182 J/g°C.

To find the quantity of heat;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

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dt = 45 - 25

dt = 20°C

Substituting the values into the equation, we have;

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An object in a fluid experiences a buoyant force from the fluid. If the object is completely immersed, on which does the magnitu
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(b) To get m3 to slide, m1 must be increased, never decreased.

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