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Aloiza [94]
3 years ago
13

Which is the next logical step in balancing the given equation? 3CO(g) + Fe2O3(s) Fe(s) + 3CO2(g)

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer : The correct option is, (C) Place the coefficient 2 in front of elemental iron.

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

3CO(g)+Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of iron are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the 'Fe'.

Thus, the balanced chemical reaction will be,

3CO(g)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO_2(g)

Elena-2011 [213]3 years ago
5 0

I believe that the answer is A.

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What properties would you expect to be different for the two enantiomers of 2-pentanol?
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Answer: direction of rotation of plane polarized light and reaction with chiral reagents.

Explanation:

Enantiomers are stereoisimers which are mirror images of each other. They possess the same physical and chemical properties except that the direction of rotation of plane polarized light and reaction with chiral reagents. (+)-2-pentanol will rotate plane polarized light to the right and react with dextrorotatory enantiomers of chiral reagents while (-)-2-pentanol will rotate plane polarized light to the left and react with leavorotatory enantiomers of chiral reagents.

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2 years ago
<img src="https://tex.z-dn.net/?f=I_%7B2%7D" id="TexFormula1" title="I_{2}" alt="I_{2}" align="absmiddle" class="latex-formula">
gogolik [260]

Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

Explanation:

An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.

A Reductant thus exactly the opposite.

Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:

I2 --> 2I-.

The oxidation number reduced from 0 to -1.

In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.

Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

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