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3 years ago

Pain in the squadron can be a sign of appemditicis

Physics

2 answers:

alexgriva [62]3 years ago

6 0

No it can also be a sign of bruising or a stomach infection <span />

timofeeve [1]3 years ago

4 0

Yes. Or it can be a sign of intestinal gas, or of constipation. Or it can be a sign of an internal bruise caused by sleeping too long on the same side. Or it can be the result of the new squadron commander cancelling all scheduled leaves.

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A book that weighs 20 N sits on a table. How big and in what direction does the force of gravity from the Earth act on the book?

taurus [48]

Answer:

A. 20 N down

Explanation:

It's asking how much force of gravity is acting on it. The book weighs 20 Newtons so that's how much gravity is being applied. Hope this helps

7 0

3 years ago

Read 2 more answers

Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawi

Nina [5.8K]

Answer:

$T_2 = 0.592$

Explanation:

Given

$T_1 = 1.48s$

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

The upper two connections are connected serially:

So, we have:

$\frac{1}{C_{up}} = \frac{1}{C} + \frac{1}{C}$

Take LCM

$\frac{1}{C_{up}} = \frac{1+1}{C}$

$\frac{1}{C_{up}}= \frac{2}{C}$

Cross Multiply

$C_{up} * 2 = C * 1$

$C_{up} * 2 = C$

Make $C_{up}$ the subject

$C_{up} = \frac{1}{2}C$

The bottom two are also connected serially.

In other words, the upper and the bottom have the same capacitance.

So, the total (C) is:

$C_1 = 2 * C_{up}$

$C_1 = 2 * \frac{1}{2}C$

$C_1 = C$

The total capacitance in (b) is calculated as:

First, we calculate the parallel capacitance (Cp) is:

$C_p = C+C$

$C_p = 2C$

So, the total capacitance (C2) is:

$\frac{1}{C_2} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C}$

$\frac{1}{C_2} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{C}$

Take LCM

$\frac{1}{C_2} = \frac{1 + 2 + 2}{2C}$

$\frac{1}{C_2} = \frac{5}{2C}$

Inverse both sides

$C_2 = \frac{2}{5}C$

Both (a) and (b) have the same resistance.

So:

We have:

Time constant is directional proportional to capacitance:

So:

$T\ \alpha\ C$

Convert to equation

$T\ =kC$

Make k the subject

$k = \frac{T}{C}$

$k = \frac{T_1}{C_1} = \frac{T_2}{C_2}$

$\frac{T_1}{C_1} = \frac{T_2}{C_2}$

Make T2 the subject

$T_2 = \frac{T_1 * C_2}{C_1}$

Substitute values for T1, C1 and C2

$T_2 = \frac{1.48 * \frac{2}{5}C}{C}$

$T_2 = \frac{1.48 * \frac{2}{5}}{1}$

$T_2 = \frac{0.592}{1}$

$T_2 = 0.592$

Hence, the time constance of (b) is 0.592 s

8 0

2 years ago

If the acceleration of an object is zero at some instant in time, what can be said about its velocity at that time? 1. It is neg

Mkey [24]

3. It is not changing at that time

Explanation:

If the acceleration of a body is zero at some instant in time, it implies that the velocity is not changing at that point in time. Velocity is the rate of change of displacement with time.

✓Acceleration and velocity shares a very close relationship.

✓ For a body to accelerate, the velocity must change. Acceleration is defined as the rate of change of velocity with time.

✓If at any point, a body moves with constant velocity i.e the velocity does not change with time, the acceleration becomes zero.

✓ For acceleration to occur, a body must change velocity.

Learn more:

Acceleration brainly.com/question/6323625

#learnwithBrainly

5 0

3 years ago

What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second?

Alexus [3.1K]

Given:-

Mass of the cart (m) = 35 kg
Speed (consider Velocity) = 1.2 m/s

To Find: Momentum of the cart.

We know,

p = mv

where,

p = Momentum,
m = Mass &
v = Velocity.

Thus,

p = (35 kg)(1.2 m/s)

→ p = 42 kg m/s (Ans.)

Conclusion:-

A. ☑️ 42 kilogram - metre per second.

6 0

3 years ago

What is a blue moon

Irina18 [472]

.
a phenomenon whereby the moon appears bluish owing to smoke or dust particles in the atmosphere

8 0

3 years ago