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Taya2010 [7]
2 years ago
8

A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma

gnetic field vector are mutually perpendicular, as?
Physics
1 answer:
Bad White [126]2 years ago
5 0

Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

brainly.com/question/23096032

#SPJ4

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The energy associated with the random motion of molecules or atoms within a substance is
Yuliya22 [10]

Answer:

C

technically B too but youre teachers not that smart so there you go

6 0
3 years ago
How are mass, distance and gpe related
Gelneren [198K]

Answer:

It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.

Explanation:

Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.

The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.

6 0
3 years ago
A resonance tube can be used to measured the speed of sound in air. A tuning fork is held above the opening of the tube and stru
LenaWriter [7]

Answer:

330.24 Hz

Explanation:

Given:

Frequency, f = 320 Hz

L1 = 25.8 cm

L2 = 78.4 cm

L3 = 131.1 cm

Let the wavelength be λ

Then, L1 which is the length of the column of air is  λ/4.

λ/4 = 25.8 cm

λ = 25.8 × 4 = 103.2 cm = 1.032 m

Then, speed of sound in air is:

v = λ f

⇒ v = 1.032 × 320 Hz

⇒ v = 330.24 m/s

7 0
3 years ago
1. A stationary 50 tonne submarine fires a missile of mass 40kg at
White raven [17]

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne=50\times 1000=50000kg

Mass of the missile m=40  kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s

8 0
3 years ago
t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is pl
DerKrebs [107]

Answer:

10

Explanation:

15 cm minus 5 cm

5 0
3 years ago
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