Answer:
<h2>The answer is 7.14 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
From the question
mass of metal = 25 g
volume = final volume of water - initial volume of water
volume = 28.5 - 25 = 3.5 mL
It's density is
We have the final answer as
<h3>7.14 g/mL</h3>Hope this helps you
Answer:- Formula of the hydrate is and it's name is Iron(III)sulfate pentahydrate.
Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.
Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.
We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:
=
=
Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.
= 1
= 5
There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is and the name of the hydrate is Iron(III)sulfate pentahydrate.
Answer:
Explanation:
First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.
Now, the fraction of vacancies is equal to the N(v)/N ratio.
Therefore:
The fraction of vacancies at 600 °C will be:
I hope it helps you!