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3 years ago

1 pts

Chemistry

1 answer:

stealth61 [152]3 years ago

3 0

Its true . air particles move faster when heated and collide with each other

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a scientists finds an organism that cannot move. it has many cells, produces spores, and gets food from its environment. in whic

lord [1]

The correct answer is : The Organism belongs in Kingdom Fungi

The explanation:

1) because Fungi can be multicellular

2) most of them cannot move.

3) They can get food by releasing digestive juices into their environment.

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4 years ago

Which of the following are properties of metals? Select all that apply.

earnstyle [38]

Answer:

All of them

Explanation:

All of those are properties of metals

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3 years ago

600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c

Ludmilka [50]

Answer:

$k=1.20x10^{-3} s^{-1}$

Explanation:

For a first order reaction the rate law is:

$v=\frac{-d[A]}{[A]}=k[A]$

Integranting both sides of the equation we get:

$\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt$

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

$ln\frac{[A]}{[A]_{0} } =-kt$

$[A]=[A]_{0}e^{-kt}$

$ln[A]=ln[A]_{0} -kt$

$k=\frac{ln[A]_{0}-ln[A]}{t}$

therefore k is

$k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}$

8 0

3 years ago

This unbalanced equation represents a chemical reaction:

inn [45]

Answer:

Explanation:

Pb(NO3)2 + 2NaI 2NaNO3 + PbI2

5 0

3 years ago

Read 2 more answers

When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solutio

8090 [49]

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

$V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL$

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3 years ago