M=3kg
p=33kg.m/s
p=m*v
v=p/m
=33/3
=11m/s
thus option (c)
Explanation:
We have,
Surface area, 
The current varies wrt time t as :

(a) At t = 2 seconds, electrical charge is given by :

(b) Current is given by :

Instantaneous current at t = 1 s is,

(c) Current is, 
Current density is given by electric current per unit area.

Therefore, it is the required explanation.
Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = (
a³ = K_s a³
Let's apply this equation to our case
a =
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s
a_w =
a_w =
4.64
Planet X
a_x =
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y =
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z =
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law
The source on the nagnetic field on the ssun is the moons pull
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
Change in speed = (60 km/hr) - (50 km/hr) = 10 km/hr
Time for the change = 12 sec
Acceleration = (10 km/hr) / (12 sec)
Acceleration = 0.8333 km/hr-sec
Convert to a unit that we can understand:
Acceleration = (0.8333 km/hr-sec)x(1000 m/km)x(hr/3600sec)
Acceleration = (833.3 / 3600) (m-hr / hr-sec²)
Acceleration = (833.3 / 3600) (m/s²)
<em>Acceleration = 0.231 m/s² </em> or 0.833 km/hr-sec²