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choli [55]
4 years ago
15

Jupiter's gravitational field is stronger than Earth's. On Jupiter, an object's__________ will be greater than on Earth. What on

e word completes the sentence?
Physics
1 answer:
vesna_86 [32]4 years ago
3 0

Answer: Weight

Explanation:The mass of an object is a measure of the quantity of matter in the object. This quantity remains constant under any circumstance.

However, the same cannot be said about the weight of such object.

The weight of the object is very much dependent on the acceleration due to gravity which is a accelerational pull (by convention-- a pull downwards).

This is why an object tends to fall when it is thrown upwards on the earth for instance.

The statements above consequently infer that since the gravitational field of Jupiter is greater than that of the earth, the acceleration due to gravity on Jupiter is greater than that on earth.

And since the weight of an object(W) is a product of its mass and the acceleration due to gravity at that point.

Consequently, the object's weight on Jupiter would be greater than its weight on earth.

Please note; The Mass of the object remains constant everywhere.

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1. What is the momentum of a 0.15 kg arrow that is traveling at 120 m/s?
Korvikt [17]

For this case we have that by definition, the momentum equation is given by:

p = m * v

Where:

m: It is the mass

v: It is the velocity

According to the data we have:

m = 0.15 \ kg\\v = 120 \frac {m} {s}

Substituting:

p = 0.15 * 120\\p = 18 \frac {kg * m} {s}

On the other hand, if we clear the variable "mass" we have:

m = \frac {p} {v}

According to the data we have:

p = 250 \frac {kg * m} {s}\\v = 5 \frac {m} {s}\\m = \frac {250} {5}\\m = 50 \ kg

Thus, the mass is 50 \ kg

Answer:

p = 18 \frac {kg * m} {s}\\m = 50 \ kg

3 0
3 years ago
What is used to calculate or determine intensity during exercise
tino4ka555 [31]
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6 0
3 years ago
Which of the following is a problem that some people blame on technology?
seropon [69]
The correct answer is B, widespread pollution. If you look closely, you can see that the other answers are not problems at all, but benefits! :)
7 0
4 years ago
Read 2 more answers
Two parallel conducting plates are separated by 4.00 cm. The electric field strength between the two plates is 5.70×10⁴ V/m.
Nookie1986 [14]

Answer:

2280 V

Explanation:

distance between the plates, d = 4 cm = 0.04 m

Electric field strength, E = 5.7 x 10^4 V/m

The formula for potential difference is given by

V = E x d

V = 5.7 x 10^4 x 0.04

V = 2280 V

thus, the potential difference between the plates is 2280 V.

6 0
4 years ago
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
4 years ago
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