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nasty-shy [4]
1 year ago
10

what is the designation given to a galaxy with a small nuclear bulge and loosely wound arms starting from a a bar through the nu

clear bulge
Physics
1 answer:
Naya [18.7K]1 year ago
5 0

In SBc galaxies, both the arms and the bar are highly resolved into star clouds and stellar associations. The arms are open in form and can start either at the ends of the bar or tangent to a ring.

<h3>Is the Milky Way a SBc galaxy?</h3>

Originally thought to be a hubble type Sb or Sc (Sbc), astronomers now believe that the Milky Way is has a central bar and is therefore a loosely wound, barred spiral galaxy – Hubble type SBbc.

<h3>What is the difference between an SBc galaxy and an Sc galaxy?</h3>

Sa (and SBa) galaxy types have tightly wound arms and large central bulges.

Sc's (and SBc's) have loosely wound arms and a small central bulge.

Learn more about SBc galaxy here:

<h3>brainly.com/question/2515850</h3><h3 /><h3>#SPJ4</h3>

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Otrada [13]

Answer:

a)   a = 3.06 10¹⁵ m / s , b)    F= 1.43  10⁻¹⁰ N, c)    F_total = 14.32 10⁻²⁶ N

Explanation:

This exercise will average solve using the moment relationship.

a ) let's use the relationship between momentum and momentum

          I = ∫ F dt = Δp

          F t = m v_{f} - m v₀

          F = m (v_{f} -v₀o) / t

 in the exercise indicates that the speed module is the same, but in the opposite direction

          F = m (-2v) / t

if we use Newton's second law

          F = m a

we substitute

            - 2 mv / t = m a

            a = - 2 v / t

let's calculate

            a = - 2 4.59 10²/3 10⁻¹³

            a = 3.06 10¹⁵ m / s

b)      F= m a

        F= 4.68 10⁻²⁶ 3.06 10¹⁵

        F= 1.43  10⁻¹⁰ N

c) if we hit the wall for 1015 each exerts a force F

            F_total = n F

            F_total = n m a

            F_total = 10¹⁵  4.68 10⁻²⁶ 3.06 10¹⁵

            F_total = 14.32 10⁻²⁶ N

8 0
3 years ago
Problem page a cyclist traveled 20 kilometers per hour faster than an in-line skater. in the time it took the cyclist to travel
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<span>Answer: skater x km/h cyclist 20 faster x + 20 km/h skater 30 km cyclist 80 km skater time = cyclist time t=d/r 30 / x = 80 /( x + 20 cross multiply 30 ( x + 20 ) = 80 x 30 x + 600 = 80 x 30 x - 80 x = -600 -50 x = -600 / -50 x = 12 km/h 12 km/h skater</span>
3 0
3 years ago
Why is it important to use the correct number of significant digits when
Artemon [7]

Answer:

D

Explanation:

Scientists use significant figures to avoid claiming more accuracy in a calculation than they actually know.

6 0
3 years ago
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Answer:

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6 0
2 years ago
A person is diving in a lake in the depth of h = 5.5 m. The density of the water is rho = 1.0 x10^3 kg/m^3. The pressure of the
Cloud [144]

Answer:a) P = Po + rho×h×g

b) P = 5.4 × 10^9 pa

c) F = P/A = (Po + rho×h×g)/A

d) 1.174×10^11N

Explanation: Using the formula

P = Po + rho×h×g

P =  1.0 x 10^5 + 1000 × 5.5 × 9.81

P = 5.4 × 10^9pa

The magnitude of the force exerted by water on the top of the person's head F at the depth h in terms of P

F = P/A = (Po + rho×h×g)/A

Using the above formula

Where A = 0.046m^2

F = P/ A = 5.4×10^9/0.046

F = 1.174×10^11N

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3 years ago
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