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Tanya [424]
3 years ago
10

A charge alters the space around it. What is this alteration of space called?

Physics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer: electric field

Explanation: when a charge is placed in space, it alters the space around it by creating an electric field.

This electric field has the ability to exert a force (f) on any test charge(q) placed within this vicinity.

This is the reason why a charge can either attract or repel another charge.

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How dose storing waste underground can be effected by ground water in aquifers<br><br>​
DiKsa [7]

Answer:

it can contaminate the water

Explanation:

I hope this helps ;)

7 0
2 years ago
A 75-kilogram hockey player is skating across the ice at a speed of 6.0 meters per second. What is the magnitude of the average
saveliy_v [14]

Answer:

(3) 690 N

Explanation:

Force: This is the product of mass and acceleration of a body. The S.I unit of force is Newton(N).

The formula for force is given as,

F = ma..................... Equation 1

Where F = force, m = mass, a = acceleration.

Also,

a = (v-u)/t................... Equation 2

Where v = Final velocity, u = initial velocity, t = time.

Given: u = 6.0 m/s, v = 0 m/s (bring to stop), t = 0.65 s.

Substitute into equation 2

a = (0-6)/0.65

a = -6/0.65

a = -9.23 m/s²

Also given: m = 75 kg

Substitute again into equation 1

F = 75(-9.23)

F = -692.25 N

The negative sign tells that the force oppose the motion of the player

F ≈ 690 N

Hence the right option is (3) 690 N

3 0
3 years ago
1. A 25.35-g piece of iron absorbs 1562.75 Joules of heat energy, and its temperature
Lera25 [3.4K]

Answer:

Q = C M T        where C is the specific, M the mass, T the temperature change

Note 1 cal = 4.19 Joules

1562.75 J / (4.19 J/cal) = 378 cal

C = Q / (M * T) = 378 cal / (25.35 g * 155 deg C)

C = .096 cal / g deg C

8 0
1 year ago
When light reflects from a surface, there is a change in its
alexandr402 [8]
The answer is: none of the above.

Explanation:

When light reflects from a surface, the frequency, wavelength, and speed do not change. They remain the same.
6 0
2 years ago
An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?
Norma-Jean [14]
Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s
6 0
2 years ago
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