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Zina [86]
3 years ago
7

What is the ph of a 0.014 M HCL solution?

Chemistry
1 answer:
Allushta [10]3 years ago
8 0

Answer:

pH = 1.853

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

[H_3O^+] = [HCl] = 0.014

pH  = -log [H^+] = -log [H_3O^+]

Substituting the available values in above equation, we can say that   the pH of the solution is equal to

- log (0.014)

pH = 1.853

pH of a 0.014 M HCL solution = 1.853

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The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
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Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
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Which of the following is not equal to 42.7 millimeters?
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The answer is: C. 0.00427 m.

A) 1 km = 1000000 mm.

d = 0.0000427 km · 1000000 mm/km.

d = 47.7 mm.

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