Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
Nuclear Fission s a power source with a very low environmental impact.
This is a uniform rectilinear motion exercise.
To start solving this exercise, we obtain the following data:
<h3>Data:</h3>
- v = 36 km/h
- d = ¿?
- t = 15 min = 0.25 hr
Minutes to hour converter
60 min = 1 hour
To calculate distance, speed is multiplied by time.
We apply the following formula: d = v * t
We substitute our data into the formula:
The distance traveled by a car moving with a speed of 36 km/h in 15 m is 9 km.
- Therefore, the correct option is "B".
The two factors that increase the size of a population are natality, which is the number of individuals that are added to the population over a period of time due to reproduction, and immigration, which is the migration of an individual into a place.