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Fynjy0 [20]
4 years ago
13

Describe a situation where you add heat to a substance or material but there is no change in temperature. What does this look li

ke on a heating curve?
Physics
1 answer:
Alisiya [41]4 years ago
6 0
ONE CAN perform this by doing an ideal experiment
by creating an isothermal system
its like you supply heat to a body and that body is present at very low temperature the amount of heat you supply is equal to the amount of heat lost by that body due to difference in the temperature of the body and the surrounding. heating curve will be constant as there is no change in the internal energy of the system ..
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An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t
Liono4ka [1.6K]

(a) 5.69 N/C, vertically downward

We can calculate the acceleration of the electron by using the SUVAT equation:

d=ut+\frac{1}{2}at^2

where

d = 4.50 m is the distance travelled by the electron

u = 0 is the initial velocity of the electron

t=3.00 \mu s = 3.0 \cdot 10^{-6} s is the time of travelling

a is the acceleration

Solving for a,

a=\frac{2d}{t^2}=\frac{2(4.50)}{(3.0\cdot 10^{-6})^2}=1.0\cdot 10^{12} m/s^2

Given the mass of the electron,

m=9.11\cdot 10^{-31} kg

We can find the electric force acting on the electron:

F=ma=(9.11\cdot 10^{-31})(1.0\cdot 10^{12})=9.11\cdot 10^{-19}N

And the electric force can be written as

F=qE

where

q=-1.6\cdot 10^{-19}C is the charge of the electron

E is the magnitude of the electric field

Solving for E,

E=\frac{F}{q}=\frac{9.11\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=-5.69 N/C

The negative sign means that the direction of the electric field is opposite to the direction of the force (because the charge is negative): since the force has same direction of the acceleration (vertically upward), the electric field must point vertically downward.

(b) Yes

We can answer the question by calculating the magnitude of the gravitational force acting on the electron, to check if it is relevant or not. The gravitational force on the electron is:

F=mg

where

m=9.11\cdot 10^{-31} kg is the mass of the electron

g=9.81 m/s^2 is the acceleration due to gravity

Substituting,

F=(9.11\cdot 10^{-31})(9.81)=8.93\cdot 10^{-30}N

We see that the gravitational force is basically negligible compared to the electric force calculated in part (a), therefore we can say it is justified to ignore the effect of gravity in the problem.

7 0
4 years ago
How can force-time and force-displacement graphs be used to find the impulse or work done?
balandron [24]

Answer:

A. Area under force-time graph & Area under force-displacement graph

Explanation:

To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.

 Impulse  = Force x time

 Work done  = Force x displacement

When we plot a graph of force and time, the area under it is the impulse.

When a graph of force and displacement is plotted, the area under is the work done.

7 0
3 years ago
7 km is equal to:<br><br> 0.7 m<br> 70 m<br> 700 m<br> 7,000 m
dusya [7]
The answer is 7000 meters.
7 0
3 years ago
Read 2 more answers
What is the relative velocity between two cars moving in the opposite direction with velocity 20m/s​
Scrat [10]
  • V_A=V_B=20m/s

Both are moving opposite

\\ \sf\ast\Rrightarrow R_{AB}=V_A-V_B

\\ \sf\ast\Rrightarrow R_{AB}=20-20

\\ \sf\ast\Rrightarrow R_{AB}=0m/s

3 0
3 years ago
Show that for a projectile d2 (v2) / dt2 = 2g2
stich3 [128]
<span>Ok, you need to derive it. Derive v^2</span>
8 0
3 years ago
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