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anygoal [31]
4 years ago
7

Methane is a type of coal. true or false

Chemistry
1 answer:
Karolina [17]4 years ago
3 0
The answer is false methane is emitted from coal
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Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions
densk [106]

Answer:

cvbn

Explanation:

5 0
3 years ago
Which postmortem parameter is fixed by 8 hours?
lara [203]

Answer:

Algor mortis is the change which is an immediately sign of death. It involves the cooling of body. The body temperature decreases as the body after death looses the control over the circulation and exchange of gases and the control over the homeostasis. The temperature decreases until the body attains equilibrium with the external environmental temperature. The postmortem cooling or algor mortis gets fixed by 8- 10 hours after death. The temperature of the body after death can be used to determine the time since death. This can be measured by determining the temperature of the rectum which is proved to be most accurate or any other orifice such as nasal, ear and vaginal can also be used.

4 0
3 years ago
Set up the math problem. But don’t do any of it. Just leave your answer as a math expression. Also be sure you’re answering clue
natta225 [31]

Answer:

Length = 681 grams / (44.5 grams / kilometers) = (681 / 44.5) kilometers

Explanation:

The diameter is there to throw us off, so ignore that. There is 681 grams of wire, and since there is 44.5 grams of copper <em>per</em> km of wire, and we want to know how many kilometers of wire makes 681 grams, the equation would be X*44.5 = 681, or X = 681/44.5


Also quora's censoring system is terrible i can't even say kilometers by adding the letter s after "km"

3 0
3 years ago
What kind of compounds are ammonia, salt, and water?
kicyunya [14]
<span>A base, an ionic molecule, and amphipathic </span>molecule
5 0
3 years ago
Read 2 more answers
Use the table of standard entropy values to determine ΔSºreaction for the following reaction:
TEA [102]

Standar molar entropies from a table:

CH3OH (l): 126.8 J / K*mol
O2 (g): 205.1 J/ K*mol
CO2(g): 213.7 J/K*mol
H2O(g): 188.8 J/J*mol

Now use the coefficients of the reaction and sum the product entropies less the reactant entropies:

4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K

Answer: option C) +3173.766 J/mol*K


8 0
3 years ago
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