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3 years ago

Which of the following statements about metalloids is true?

Chemistry

2 answers:

Klio2033 [76]3 years ago

7 0

Metalloids had properties that fall between those of metals and nonmetals (I believe that to be correct-.-)

aleksklad [387]3 years ago

3 0

Answer: Option (c) is the correct answer.

Explanation:

Metalloids are the substances or elements that show properties of both metals and non-metals.

Metals are good conductors of heat and electricity. They have shiny surface and can be drawn into thin wires and sheets.

Whereas non-metals are bad conductors of heat and electricity. They are brittle in nature and are not shiny.

Similarly, metalloids are shiny but they are brittle at the same time with a relatively good electrical conductivity.

Thus, we can conclude that the statement, metalloids have properties that fall between those of metals and nonmetals, is true about metalloids.

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at

Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0

3 years ago

A runner travels at a constant speed of 4 m/s. What happens to the velocity of the runner when the runner changes direction?

ANTONII [103]

Answer:

4m/s in the direction of the turn

Explanation:

The velocity of an object is the rate of change of its position with respect to a frame of reference.

Assuming the runner stays the same speed as he turns, his velocity will be 4m/s in the speed he turns.

5 0

3 years ago

What do you understand by valency electron and valency shell?

jasenka [17]

Answer:

<h2>total no. of electron present in Valency shell is called valency electron </h2><h2>___________________</h2>

<h2>valency shell is that in which last electron is present</h2>

7 0

2 years ago

What is the expected oxidation state for the most common ion of element 2

lozanna [386]

Answer: 1+

Justification:

The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.

The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.

The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.

Therefore, the expected oxidation state for the most common ion of element 2 is 1+.

3 0

3 years ago

How to identify Double replacement

BARSIC [14]

Answer:

The easiest way to identify a double displacement reaction is to check to see whether or not the cations exchanged anions with each other.

Explanation:

if the states of matter are cited, is to look for aqueous reactants and the formation of one solid product (since the reaction typically generates a precipitate).

6 0

3 years ago