It goes in the downward direction
Answer:
5.02 m
Explanation:
Applying the formula of maximum height of a projectile,
H = U²sin²Ф/2g...................... Equation 1
Where H = maximum height, U = initial velocity, Ф = angle, g = acceleration due to gravity.
Given: U = 46 ft/sec = 14.021 m/s, Ф = 45°
Constant: g = 9.8 m/s²
Substitute these values into equation 1
H = (14.021)²sin²45/(2×9.8)
H = 196.5884×0.5/19.6
H = 5.02 m.
Hence the ball goes 5.02 m high
Take the barometer to the roof of the building. Drop the barometer from the edge of the roof, and, with your wrist watch or a stop watch, measure the time it takes for the barometer to hit the ground or the street below. Then the height of the roof, in meters, is 4.9 times the square of the time in seconds.
Answer:
366 K
Explanation:
T₀ = Constant Temperature of deep lake = 293.0 K
T = Temperature of hot reservoir connected to carnot engine = ?
η = Efficiency of Carnot engine during the operation
Efficiency of Carnot engine is given as
Inserting the values
T = 366 K
Answer:
The time required for the package to hit the ground = 14.63 seconds.
Explanation:
<u>Considering vertical motion of care package</u>:-
Initial velocity, u = 0 m/s
Acceleration , a = 9.81 m/s²
Displacement, s = 1050 m
We have equation of motion s= ut + 0.5 at²
Substituting
s= ut + 0.5 at²
1050 = 0 x t + 0.5 x 9.81 x t²
t = 14.63 seconds
The time required for the package to hit the ground = 14.63 seconds.
