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MAXImum [283]
3 years ago
9

Predict the velocity vy when y=-3.5 meters. Use the average acceleration you calculated in Activity 1. Use the formula v = Vo2 +

2ay, where v = final velocity, Vo = initial velocity, a = average acceleration, and y = y displacement. (Note that v is the final velocity in the y direction: Vy.)​
Physics
1 answer:
atroni [7]3 years ago
3 0

Answer:

v^2=0^2 + 2(-9.3)(-3.5)

v=vy=the square root of 65.1= 8.1 m/s

Explanation:

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The acceleration due to gravity vector is always in the ____ direction.
finlep [7]
It goes in the downward direction
4 0
3 years ago
A ball is shot at an angle of 45 degrees into the air with initial velocity of 46 ft/sec. Assuming no air resistance, how high d
mestny [16]

Answer:

5.02 m

Explanation:

Applying the formula of maximum height of a projectile,

H = U²sin²Ф/2g...................... Equation 1

Where H = maximum height, U = initial velocity, Ф = angle, g = acceleration due to gravity.

Given: U = 46 ft/sec = 14.021 m/s, Ф = 45°

Constant: g = 9.8 m/s²

Substitute these values into equation 1

H = (14.021)²sin²45/(2×9.8)

H = 196.5884×0.5/19.6

H = 5.02 m.

Hence the ball goes 5.02 m high

8 0
3 years ago
How could you use the barometer to determine the height of a building?
Nady [450]
Take the barometer to the roof of the building. Drop the barometer from the edge of the roof, and, with your wrist watch or a stop watch, measure the time it takes for the barometer to hit the ground or the street below. Then the height of the roof, in meters, is 4.9 times the square of the time in seconds.
5 0
3 years ago
A Carnot heat engine has an efficiency of 0.200. If it operates between a deep lake with a constant temperature of 293.0 K and a
Dimas [21]

Answer:

366 K

Explanation:

T₀ = Constant Temperature of deep lake = 293.0 K

T = Temperature of hot reservoir  connected to carnot engine = ?

η = Efficiency of Carnot engine during the operation

Efficiency of Carnot engine is given as

\eta = 1-\frac{T_{o}}{T}

Inserting the values

0.200 = 1-\frac{293.0}{T}

T = 366 K

3 0
3 years ago
An airplane is moving horizontally with a constant velocity of (+ 115 m/s) at altitude of 1050 m. The directions to the right an
PtichkaEL [24]

Answer:

The time required for the package to hit the ground = 14.63 seconds.

Explanation:

<u>Considering vertical motion of care package</u>:-

Initial velocity, u =  0 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 1050 m

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

    1050 = 0 x t + 0.5 x 9.81 x t²

    t = 14.63 seconds

The time required for the package to hit the ground = 14.63 seconds.

7 0
3 years ago
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