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Scilla [17]
2 years ago
8

What is the acceleration due to gravity of an object with a mass of 10000 g?

Physics
1 answer:
Aleks [24]2 years ago
7 0

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

<h3>What is gravitational constant?</h3>

According to Sir Isaac Newton's rule of universal gravitation and Albert Einstein's theory of general relativity, the gravitational constant, indicated by the capital G, is an empirical physical constant that is used to calculate the gravitational effects.

<h3>According to the given information:</h3>

mass of object = 10kg

gravitational constant = 6.67 x 10^-11

radius of earth  = 6.3 x 10^6

we know that:

acceleration due to gravity = GM/R²

                                             = ((6.67 x 10^-11)*10)/(6.3 x 10)²

Solving this we get :

42.02 x 10^-16 m/s²

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

To know more about acceleration due to gravity visit:

brainly.com/question/13860566

#SPJ4

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The tendency of an atom to pull electrons toward itself is referred to as its _____. the tendency of an atom to pull electrons t
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3 years ago
The angular speed of digital video discs (DVDs) varies with whether the inner or outer part of the disc is being read. (CDs func
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Answer:

α = 0.0135 rad/s²

Explanation:

given,

t = 133 min = 133 x 60 = 7980 s

angular speed varies from 570 rpm to 1600 rpm

now,

570 rpm = 570 \times \dfrac{2\pi}{60}

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1600 rpm =  = 570 \times \dfrac{2\pi}{60}

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using equation of rotational motion

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8 0
3 years ago
1)
Ket [755]

Answer:

1) D

2) A

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1) Each group has the same number of valence electrons, which are the outer electrons.

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3 years ago
A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t
borishaifa [10]

Answer:

Angular acceleration will be 18.84rad/sec^2

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity \omega _i=0rev/sec

And final angular velocity \omega _f=24rev/sec

Time is given as t = 8 sec

From equation of motion

We know that \omega _f=\omega _i+\alpha t

24=0+\alpha \times 8

\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2

So angular acceleration will be 18.84rad/sec^2

4 0
3 years ago
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