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storchak [24]
3 years ago
11

A block with mass m = 4.3 kg is attached to two springs with spring constants kleft = 35 N/m and kright = 48 N/m. The block is p

ulled a distance x = 0.23 m to the left of its equilibrium position and released from rest.What is the magnitude of the net force on the block (the moment it is released)?
Physics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

Explanation:

A restoring force is created when a spring is either stretched or compressed.

Restoring force created by first spring = spring constant x contraction

= 35 x .23

= 8.05 N .

It will act towards the right .

Restoring force created by second spring = spring constant x extension

= 48 x .23

= 11.04 N .

It will also act towards the right .

Total force created due to contraction in the first spring and extension in the right spring = 8.05  +11.04 N

= 19.09 N .

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A solid cylinder of mass M = 45 kg, radius R = 0.44 m and uniform density is pivoted on a frictionless axle coaxial with its sym
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Answer:

w_f = 1.0345 rad/s

Explanation:

Given:

- The mass of the solid cylinder M = 45 kg

- Radius of the cylinder R = 0.44 m

- The mass of the particle m = 3.6 kg

- The initial speed of cylinder w_i = 0 rad/s

- The initial speed of particle V_pi = 3.3 m/s

- Mass moment of inertia of cylinder I_c = 0.5*M*R^2

- Mass moment of inertia of a particle around an axis I_p = mR^2

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                                     L_i = L_f

- Initially, the particle is at edge at a distance R from center of cylinder axis with a velocity V_pi = 3.3 m/s contributing to the initial angular momentum of the system by:

                                    L_(p,i) = m*V_pi*R

                                    L_(p,i) = 3.6*3.3*0.44

                                    L_(p,i) = 5.2272 kgm^2 /s

- While the cylinder was initially stationary w_i = 0:

                                    L_(c,i) = I*w_i

                                    L_(c,i) = 0.5*M*R^2*0

                                    L_(c,i) = 0 kgm^2 /s

The initial momentum of the system is L_i:

                                    L_i = L_(p,i) + L_(c,i)

                                    L_i = 5.2272 + 0

                                    L_i = 5.2272 kg-m^2/s

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                                   L_(p,f) = I_p*w_f

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                                   L_(c,f) = I_c*w_f

- Note, the final angular velocity w_f are same for both particle and cylinder. Every particle on a singular incompressible (rigid) body rotates at the same angular velocity around a fixed axis.

                                  L_f = L_(p,f) + L_(c,f)

                                  L_f = I_p*w_f + I_c*w_f

                                  L_f = w_f*(I_p + I_c)

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                                  w_f =  5.2272/ 5.05296

                                  w_f = 1.0345 rad/s

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