Answer:
0.231 m/s
Explanation:
m = mass attached to the spring = 0.405 kg
k = spring constant of spring = 26.3 N/m
x₀ = initial position = 3.31 cm = 0.0331 m
x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m
v₀ = initial speed = 0 m/s
v = final speed = ?
Using conservation of energy
Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy
(0.5) m v₀² + (0.5) k x₀² = (0.5) m v² + (0.5) k x²
m v₀² + k x₀² = m v² + k x²
(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²
v = 0.231 m/s
Answer:
I think is o or mavey it could be D
Answer:
4.4 m/s
Explanation:
momentum is always conserved so we can use conversation of momentum to solve the question, also momentum is a vector quantity ( it has magnitude and direction) which is the product of the bodies mass and velocity.
conservation law of momentum relates by the formula below:
momentum before collision = momentum after collision
M1U1 + M2U2 = M1V1 + M2V2
in the case of this two, the formula becomes
M1U1 + M2U2 = V (M1 + M2) since she jumped into his arm
there masses are M1 = 75.6 kg M2 = 59 kg and their velocities are U1 = 3.7 m/s and U2 = 5.4 m/s, their common velocity after collision = V since their motion is backward the formula becomes
-M1U1 - M2U2 = V(M1 + M2)
substitute the values into the equations
(-75.6 × 3.7 ) + (- 59 × 5.4) = V ( 75.6 + 59)
- 598.32 = 134.6 V
divide both side by 134.6
V = - 598.32 / 134.6 = -4.445 m/s = -4.4 m/s to nearest tenth the negative means in the same backward direction
Answer:
Explanation:
Usually the angle between the y axis and x axis is 90° and we know that for furthest travel the degree angle must be 45° with the horizontal, Mo must release the ball about halfway between straight ahead and straight up