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Svetlanka [38]
2 years ago
15

PI3 trigonal planar trigonal pyramidal tetrahedral

Chemistry
1 answer:
EleoNora [17]2 years ago
3 0
  1. The bond polarities of a molecule of ammonia (NH₃) are <u>polar</u>.
  2. The molecular shape of a molecule of ammonia (NH₃) is <u>trigonal pyramidal</u>.
  3. The molecule of a molecule of ammonia (NH₃) is <u>polar</u>.

<h3>The types of covalent bond.</h3>

In Chemistry, there are two (2) main types of covalent bond and these include the following:

  • Polar covalent bond.
  • Non-polar covalent bond.

<h3>What is electronegativity?</h3>

Electronegativity can be defined as the ability or tendency of the atom of an chemical element to attract any shared pair of electrons.

In Chemistry, the difference in electronegativity between an atom of nitrogen (N) and hydrogen (H) causes electrons to preferentially orbit an atom of nitrogen (N), thereby, making the bond polar.

Furthermore, the molecular shape of a molecule of ammonia (NH₃) is <u>trigonal pyramidal</u> and the molecule of a molecule of ammonia (NH₃) is <u>polar</u>.

Read more on bond polarities and electronegativity here: brainly.com/question/12789975

#SPJ1

<u>Complete Question:</u>

Describe the characteristics of a molecule of ammonia (NH3). The Lewis structure and table of electronegativities are given.

The bond polarities are BLANK 1, the molecular shape is BLANK 2, and the molecule is BLANK 3.

blank 1 options: nonpolar, polar

blank 2 options: bent, linear, tetrahedral, trigonometry planar, trigonal pyramidal.

Blank 3 options: nonpolar, polar

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If excess sulfuric acid reacts with 30 grams of sodium chloride, how many grams of HCl are produced
vodka [1.7K]
Consider the Chemical Reaction first:

Reaction: H₂SO₄ + 2 NaCl → 2 HCl + Na₂SO₄

Now, Given mass of NaCl = 30 g
Molar mass of Nacl = 58 g/mol

Now, Number of moles of NaCl = 30/58 = 0.517 mol

Balance the equation, For every 2 molecules of NaCl, 2 molecules of HCl formed, so the number of moles would be same.

Hence, Number of moles of HCl = 0.517 mol

Now, Mass of HCl = Molar mass of HCl * Number of moles
Mass = 36 * 0.517    [ Molar mass of HCl = 36 ]
Mass = 18.62 g

In short, Your Answer would be: 18.62 Grams

Hope this helps!
6 0
3 years ago
A small sack of sand has a density of 1.5 g/cm3 and a mass of 1500 g. How much space (volume) does the sand occupy?
d1i1m1o1n [39]
The answer would be 1000 cm3
8 0
3 years ago
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The melting of ice cubes is an exothermic reaction.<br>true or false​
scoray [572]

Answer:

false

Explanation:

5 0
4 years ago
Read 2 more answers
What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

  • d = m/V, where d is the density, m is the mass and V is the volume.
  • We have the mass m = 0.50 g, so we must get the volume V.
  • To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

  • Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
  • Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
6 0
4 years ago
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
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