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cluponka [151]
2 years ago
15

Which type of nuclear decay is the radioactive isotope fe2659 likely to undergo?

Chemistry
1 answer:
jekas [21]2 years ago
3 0

Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

Whenever there are too many protons or even neutrons in a nucleus, one of the protons and neutrons will turn into the other, which is known as beta decay. During beta minus decay, a neutron transforms into a proton, electron, as well as antineutrino.

Fe_{26} ^{59} → Co_{27} ^{59} +\beta_{1}  ^{0}

It can be seen that after the beta minus decay Fe changes into Co.

In beta decay , decrease in atomic number by one unit Fe atom get converted into Co atom.

Neutron-rich nuclei often decay by producing both an electron and an antineutrino.

Therefore, Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

To know more about  radio-active isotope

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Which statements correctly describe sound ( select all that apply)
xeze [42]

Answer:

The answer is all of the above

Explanation:

Sound has waves which are compression waves and those waves transfer into energy molecules. Sound is heard by human ears. Sound waves can behave in predictable ways. All sound requires a medium through to travel

5 0
3 years ago
Ayyyyyy<br> todays my birthday<br> hmu plzzz
SVEN [57.7K]

Answer:

happy bday

Explanation:

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3 0
3 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
USPshnik [31]

Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

Learn more about Partial pressure here:

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6 0
2 years ago
Which metal in Period 5 is very reactive and has two valence electrons in each atom? rubidium (Rb) strontium (Sr) zirconium (Zr)
vladimir1956 [14]
<h3>Answer:</h3>

           Strontium (Sr)

<h3>Explanation:</h3>

                        The condition given in statement is the presence of two valence electron. Hence, first we found the electronic configuration of given atoms as follow;

                       Rubidium                         [Kr] 5s¹

                      Strontium                        [Kr] 5s²

                       Zirconium                         [Kr] 4d² 5s²

                      Silver                                 [Kr] 4d¹⁰ 5s¹

From above configurations it is cleared that only Strontium and Zirconium has two electrons in its valence shell.

We also know that s-block elements are more reactive than transition elements due to less shielding effect in transition elements hence, making it difficult for transition metals to loose electrons as compared to s-block elements. Therefore, we can conclude that Strontium present in s-block with two valence electrons is the correct answer.

4 0
3 years ago
Read 2 more answers
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