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cluponka [151]
2 years ago
15

Which type of nuclear decay is the radioactive isotope fe2659 likely to undergo?

Chemistry
1 answer:
jekas [21]2 years ago
3 0

Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

Whenever there are too many protons or even neutrons in a nucleus, one of the protons and neutrons will turn into the other, which is known as beta decay. During beta minus decay, a neutron transforms into a proton, electron, as well as antineutrino.

Fe_{26} ^{59} → Co_{27} ^{59} +\beta_{1}  ^{0}

It can be seen that after the beta minus decay Fe changes into Co.

In beta decay , decrease in atomic number by one unit Fe atom get converted into Co atom.

Neutron-rich nuclei often decay by producing both an electron and an antineutrino.

Therefore, Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

To know more about  radio-active isotope

brainly.com/question/4421649

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How many moles are in 8.63 x 103 atoms of Li?
Ira Lisetskai [31]
<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})
  2. Multiply/Divide:                \displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

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The molar solubility of magnesium carbonate is 1.8 × 10–4 mol/l. What is ksp for this compound?
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Answer:

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Explanation:

Let's consider the solution of magnesium carbonate.

MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

We can relate the molar solubility (S) with the solubility product (Ksp) using an ICE chart.

         MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

I                             0                0

C                          +S              +S

E                            S                S

The Ksp is:

Ksp = [Mg²⁺] × [CO₃²⁻] = S × S = S² = (1.8 × 10⁻⁴)² = 3.2 × 10⁻⁸

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