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cluponka [151]
2 years ago
15

Which type of nuclear decay is the radioactive isotope fe2659 likely to undergo?

Chemistry
1 answer:
jekas [21]2 years ago
3 0

Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

Whenever there are too many protons or even neutrons in a nucleus, one of the protons and neutrons will turn into the other, which is known as beta decay. During beta minus decay, a neutron transforms into a proton, electron, as well as antineutrino.

Fe_{26} ^{59} → Co_{27} ^{59} +\beta_{1}  ^{0}

It can be seen that after the beta minus decay Fe changes into Co.

In beta decay , decrease in atomic number by one unit Fe atom get converted into Co atom.

Neutron-rich nuclei often decay by producing both an electron and an antineutrino.

Therefore, Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

To know more about  radio-active isotope

brainly.com/question/4421649

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m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

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m = mass of solution = 100 g

q = heat gained = ?

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T_{initial} = initial temperature = 28.9^oC

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q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

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Now we have to calculate the enthalpy change during the reaction.

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\Delta H = enthalpy change = ?

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\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

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