Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (iv
1 answer:
Electron, photon and proton carry momentum .
- De Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.
- De Broglie's relationship is given by
...(1)
- Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.
Equation (1) can be written as where λ is known as de Broglie wavelength and p is momentum , h = Plank’s constant
For photon , the momentum is given by ...(2) where c is the speed is the speed of light .
From equation (1) and (2) we can conclude that electron, photon and proton carry momentum .
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Answer:
(a)
(b)
(c) K.E. = 21.168 J
(d)
Explanation:
Given:
- mass of a block, M = 3.6 kg
- initial velocity of the block,
- constant downward acceleration,
That a constant upward acceleration of
is applied in the presence of gravity.
∴
- height through which the block falls, d = 4.2 m
(a)
Force by the cord on the block,
∴Work by the cord on the block,
We take -ve sign because the direction of force and the displacement are opposite to each other.
(b)
Force on the block due to gravity:
∵the gravity is naturally a constant and we cannot change it
∴Work by the gravity on the block,
(c)
Kinetic energy of the block will be equal to the net work done i.e. sum of the two works.
mathematically:
K.E. = 21.168 J
(d)
From the equation of motion:
putting the respective values:
is the speed when the block has fallen 4.2 meters.