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sladkih [1.3K]
1 year ago
8

Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (iv

) Which carry momentum?
Physics
1 answer:
DiKsa [7]1 year ago
4 0

Electron, photon and proton carry momentum .

  • De Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.
  • De Broglie's relationship is given by \lambda=\frac{h}{mv}   ...(1)
  • Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

Equation (1) can be written as   \lambda=\frac{h}{p}   where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant

For photon , the momentum is given by   p=\frac{E}{c}   ...(2)  where c is the speed is the speed of light .

From equation (1) and (2) we can conclude that electron, photon and proton carry momentum .

Learn about more photon momentum here :

brainly.com/question/13112527

#SPJ4

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Light would most likely be transmitted through A. A mirror B. A stone C. A leaf D. A window
ohaa [14]
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Read 2 more answers
What speed would a fly with a mass of 0.55g need in order to have a kinetic energy of 7.6 •10^4 j?
masya89 [10]

Answer:

16613 m/s

Explanation:

Given that

mass of the fly, m = 0.55 g = 0.55*10^-3 kg

Kinetic Energy of the fly, E = 7.6*10^4 J

Speed of the fly, v = ? m/s

We know that the Kinetic Energy is that energy that an object, in this case, the fly, possesses due to its motion.

The Kinetic Energy, KE of any object is represented by the formula

KE = 1/2 * m * v²

If we substitute the values in the relation, we have,

7.6*10^4 = 1/2 * 0.55*10^-3 * v²

v² = (15.2*10^4) / 0.55*10^-3

v² = 2.76*10^8

v = √2.76*10^8

v = 16613 m/s

Thus, the fly would need a speed of 16.6 km/s in order to have a Kinetic Energy of 7.6*10^4 J

7 0
3 years ago
You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find
ivanzaharov [21]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

<u>ω = 1.57 rad/s </u>

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

<u>ac = 4.92 m/s² </u>

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

<u>μs = 0.5</u>

7 0
2 years ago
Which statements describe what is occurring at t=5 seconds? Check all that apply
Alex73 [517]

Answer: The object changed directions

The object sped up

Explanation:

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