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dangina [55]
2 years ago
14

Branched-chain amino acids (bcaas), commonly known as a supplement to support recovery and stimulate muscle growth, may also ser

ve to:_____.
Chemistry
1 answer:
Eva8 [605]2 years ago
5 0

BCAA supplements are commonly taken to boost muscle growth and enhance exercise performance.

They may also help with weight loss and reducing fatigue after exercise. This article contains all the most important information about branched-chain amino acids and their benefits.

<h3><u>What are purposes of Branched-chain amino acids (bcaas) ?</u></h3>
  • Leucine, isoleucine, and valine are the three essential amino acids that make up the branched-chain amino acids (BCAAs).
  • Since they are vital, your body cannot create them on its own and you must get them through food.
  • BCAA supplements have been demonstrated to increase muscular mass, lessen muscle pain, and reduce muscle fatigue.
  • They have also been used successfully in hospitals to lessen liver disease symptoms and stop or slow down muscle loss.
  • However, since the majority of people consume enough BCAAs from their diets, taking supplements is unlikely to provide any further advantages.

To view more about amino acids, refer to:

brainly.com/question/15969022

#SPJ4

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The answer is: (5696 J) / (155 g) / (40.0 - 25.0)°C = 2.45 J/g·°C 
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What natural resources are used to make chloroquine?
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What is the approximate time of day, based on the position of the Sun in the sky?
Ivenika [448]

Answer:

sunrise

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Which of these describes how heat is transfenned by conduction
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4 years ago
Convert 4.50 e23 atoms of CO to grams.
hichkok12 [17]

Answer:

10.4664 grams of CO

Explanation:

Remark

There's a couple of things you must look out for in this question.

1. The use of the term atoms. There are 2 atoms in each mol of CO

2. You need to divide by 2 to find the number of molecules which will lead to moles.

<u>Step one</u>

Divide the number of atoms by 2

4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.

<u>Step Two</u>

Find the number of moles of CO

1 mol of anything is 6.02 * 10^23 molecules in this case

x  = 2.25 * 10^23 molecules

1/x = 6.02 * 10^23/2.25 * 10 ^23            Cross multiply

1 * 2.25 * 10^23 = 6.02*10^23 * x           Divide by 6.02 * 10^23

2.25 * 10 ^ 23 / 6.02 * 10^23 = x

x = .3738 moles of CO

<u>Step Three</u>

Find the gram molecular mass of CO

C = 12

O = 16

1 mole = 12 + 16  = 28 grams.

<u>Step Four</u>

Find the number of gram in 0.3738 mols

1 mol = 28 grams

0.3738 mol = x                Cross multiply

x = 28 * 0.3738

x = 10.4664 grams

7 0
3 years ago
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