Answer:
The molality of isoborneol in camphor is 0.53 mol/kg.
Explanation:
Melting point of pure camphor= T =179°C
Melting point of sample = 
= 165°C
Depression in freezing point = 
Depression in freezing point is also given by formula:
= The freezing point depression constant
m = molality of the sample
i = van't Hoff factor
We have: = 40°C kg/mol
i = 1 ( organic compounds)
The molality of isoborneol in camphor is 0.53 mol/kg.
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Contractions of the skeletal muscles
As it puts pressure and moves the blood along
Plants fertilized one per week with Super Plant Food Formula have been shown in testing to produce twice as much fruit as plants that are not.
That answer is the most scientific because it states the word "testing" and in science they do a bunch of test to make a scientific claim.
