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2 years ago

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Which option correctly shows the concentration of H₂O* ions in pure water? (1 point)

1 answer:

Lostsunrise [7]2 years ago

7 0

H2O is present at a calculated value of 1.0 x 107 moles per liter.

The balance of neutral water molecules and the ions they generate controls the chemistry of aqueous solutions.

H3O+(aq) + 2 H2O(l) + OH- (aq)

1.0 x 10-7 M [H3O+] = [OH-]

As a result, adding an acid to water affects the concentration of both H3O+ and OH- ions. Acids raise the concentration of the H3O+ ion in water since they are a source of this ion. However, the amount to which water dissociates is reduced when an acid is added. As a result, the concentration of the OH- ion significantly drops. The concentration of OH- ions rises as a result of adding a base. The H3O+ and OH- ion concentrations are combined to equal Kw once the system reaches equilibrium. Naturally, the only method to do this is to reduce the concentration of the H3O+ ion.

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Which system helps regulate fluids in the body?

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The answer is A. Urinary system

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A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They

soldier1979 [14.2K]

Answer:

a. $\thta=71^{\circ}$

b. $v_f=3.78 m/s$

Explanation:

We are given that

$m_1=53 kg$

$v_1=2.9 m/s$

$m_2= 72 kg$

$v_2=6.2 m/s$

a.We have to find the angle

$\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}$

$\theta=71^{\circ}$

b. We have to find the speed $v_f$

According to law of conservation of momentum

$m_1v_1=(m_1+m_2)v_fcos\theta$

$53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f$

$v_f=\frac{153.7}{40.7}=3.78 m/s$

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3 years ago

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Stolb23 [73]

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3 years ago

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The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object

lilavasa [31]

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

$F_{f} =$ μ * $F_{n}$

where,

$F_{f}$ = force of friction

μ = coefficient of friction

$F_{n}$ = normal force

Given,

μ $= 0.10, m = 8.0 kg$

We know,

$F_{n} = mg$

$F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N$

Subsituing the values in equation:

$F_{f} =$ μ * $F_{n}$

$F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N$

The force of friction is 78.4 N.

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1 year ago

A solid metal ball and a hollow plastic ball of the same external radius are released from rest in a large vacuum chamber. When

S_A_V [24]

Answer:

time of fall and the final velocity

Explanation:

the mass of solid ball is more than the mass of hollow ball.

According to the third equation of motion

v² = u² + 2gh

As the final velocity v does not depend on the mass of the object, so the final velocity of both the ball is same.

According to the first equation of motion

v = u + gt

As v is same for both the balls, the time is also same for both the balls.

So, they both have same time of fall and final velocity.

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3 years ago