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Natali [406]
1 year ago
10

Which option correctly shows the concentration of H₂O* ions in pure water? (1 point)

Physics
1 answer:
Lostsunrise [7]1 year ago
7 0

H2O is present at a calculated value of 1.0 x 107 moles per liter.

The balance of neutral water molecules and the ions they generate controls the chemistry of aqueous solutions.

H3O+(aq) + 2 H2O(l) + OH- (aq)

1.0 x 10-7 M [H3O+] = [OH-]

As a result, adding an acid to water affects the concentration of both H3O+ and OH- ions. Acids raise the concentration of the H3O+ ion in water since they are a source of this ion. However, the amount to which water dissociates is reduced when an acid is added. As a result, the concentration of the OH- ion significantly drops. The concentration of OH- ions rises as a result of adding a base. The H3O+ and OH- ion concentrations are combined to equal Kw once the system reaches equilibrium. Naturally, the only method to do this is to reduce the concentration of the H3O+ ion.

Learn more about Concentration here-

brainly.com/question/10725862

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A runner drank a lot of water during a race. What is the expected path of the extra filtered water molecules?
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Answer:

Afferent arteriole, glomerulus, nephron tubule, collecting duct

Explanation:

Blood enters the kidney through the renal artery, a thick branch from the descending aorta. In the hilum, it is divided into several branches that are distributed through the lobes of the kidney and are branching forming numerous afferent arterioles that form the glomerular clew. It is precisely the walls of these capillaries that act as ultrafilters, allowing small particles to pass through.

Blood that flows through the <u>afferent arteriole</u> circulates through the capillary vessels of the kidney (the true capillaries that provide the kidney with oxygen and nutrients necessary for its function). These capillaries are grouped together to form the renal vein which, in turn, pours into the inferior vena cava.

Given the function of the kidneys to eliminate waste products through urine, it is not surprising that these organs are the ones that receive the most blood per gram of weight. One way to express renal blood flow is by considering the renal fraction or fraction of cardiac output that passes through the kidneys.

The regulation of blood flow in the glomeruli is achieved by three formations: the polar bearing, the Goormaghtigh cells and the dense macula. The polar bearing consists of a thickening of the afferent arteriole wall before it enters the <u>renal glomerulus</u>. The arteriole loses its elastic membrane, the endothelium becomes discontinuous and the middle tunic is arranged in two layers, formed by secretory cells: these secretory cells produce Angiotensin and Erythropoietin.

Goormaghtigh cells are arranged at an angle between afferent and effector arterioles and meet in small columns. They are closely related to polar bearing cells. Between both formations is the dense macula (or Zimmerman's dense macula) that is in contact with the distal tubule and afferent arteriole just before it penetrates the glomerulus. These three formations, polar bearing, Goormaghtigh cells and dense macula form the juxtaglomerular apparatus that regulates the blood flow in the glomerulus.

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The reabsorption and secretion are achieved with the mechanisms of Cotransporte and Contratransporte established in the nephrons and associated collection ducts. Blood filtration occurs in the glomerulus, a capping of capillaries that is inside a Bowman's capsule.

Liquid flows from the nephron in the <u>collecting duct</u> system. This segment of the nephron is crucial to the process of water conservation by the body. In the presence of the antidiuretic hormone (ADH; also called vasopressin), these ducts become water permeable and facilitate their reabsorption, thus concentrating the urine and reducing its volume. Conversely, when the body must remove excess water, for example after drinking excess fluid, ADH production is decreased and the collecting tubule becomes less permeable to water, making the urine diluted and abundant.

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Answer:

The number of input force is the same as output. ... If it equals once, then both numbers are equal making it the same.Explanation:

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