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2 years ago

Which option correctly shows the concentration of H₂O* ions in pure water? (1 point)

Physics

1 answer:

Lostsunrise [7]2 years ago

7 0

H2O is present at a calculated value of 1.0 x 107 moles per liter.

The balance of neutral water molecules and the ions they generate controls the chemistry of aqueous solutions.

H3O+(aq) + 2 H2O(l) + OH- (aq)

1.0 x 10-7 M [H3O+] = [OH-]

As a result, adding an acid to water affects the concentration of both H3O+ and OH- ions. Acids raise the concentration of the H3O+ ion in water since they are a source of this ion. However, the amount to which water dissociates is reduced when an acid is added. As a result, the concentration of the OH- ion significantly drops. The concentration of OH- ions rises as a result of adding a base. The H3O+ and OH- ion concentrations are combined to equal Kw once the system reaches equilibrium. Naturally, the only method to do this is to reduce the concentration of the H3O+ ion.

Learn more about Concentration here-

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3 years ago

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Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

Emf induced in the coil represented by formula

∈ = $-N\frac{d\phi}{dt}$ ...................(1)

Where:

. $\phi = BAcos\theta$ { B is magnetic field }

{A is cross-sectional area}

. $N =$ No. of turns in coil.

. $\frac{d\phi}{dt} =$ Rate change of induced Emf.

Here,

Considering the case :-

$N1 = 2N$ & $\frac{d\phi1}{dt} = 2\frac{d\phi}{dt}$

Putting these value in the equation (1) and finding the new emf induced (∈1)

∈1 = $-N1\times\frac{d\phi1}{dt}$

∈1 = $-2N\times2\frac{d\phi}{dt}$

∈1 = $4 [-N\times\frac{d\phi}{dt}]$

∈1 = 4∈ ...............{from Equation (1)}

Hence,

The Resultant Induced Emf in coil is 4∈.

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