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2 years ago

Which option correctly shows the concentration of H₂O* ions in pure water? (1 point)

Physics

1 answer:

Lostsunrise [7]2 years ago

7 0

H2O is present at a calculated value of 1.0 x 107 moles per liter.

The balance of neutral water molecules and the ions they generate controls the chemistry of aqueous solutions.

H3O+(aq) + 2 H2O(l) + OH- (aq)

1.0 x 10-7 M [H3O+] = [OH-]

As a result, adding an acid to water affects the concentration of both H3O+ and OH- ions. Acids raise the concentration of the H3O+ ion in water since they are a source of this ion. However, the amount to which water dissociates is reduced when an acid is added. As a result, the concentration of the OH- ion significantly drops. The concentration of OH- ions rises as a result of adding a base. The H3O+ and OH- ion concentrations are combined to equal Kw once the system reaches equilibrium. Naturally, the only method to do this is to reduce the concentration of the H3O+ ion.

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You might be interested in

speed is the ratio of the distance an object moves to a. the direction the object moves. b. the amount of time needed to travel

Dennis_Churaev [7]

It is the ratio of distance an object moves to the amount of time needed to travel the distance. Option b.

5 0

3 years ago

Read 2 more answers

Safety belts and occupant protection systems are installed to reduce the harmful effects of the force of _____ during a collisio

Phantasy [73]

To lessen the negative impacts of the force generated during a collision, safety belts and occupant protective relays are installed.

Importance of safety belts:

The purpose of a seat belt usually referred to as a safety belt or a safety belt, is to protect the driver or an occupant of a vehicle from a potentially dangerous movement that may occur during an accident or an abrupt stop. By minimizing the power of secondary hits with interior striking hazards, maintaining proper occupant positioning for the airbag, and preventing people from being expelled from the vehicle after an accident or if the automobile rolls over, seat belts help minimize the chance of a fatal accident in traffic collisions. When the car is moving, the passenger and the driver move together with it at the same pace.

The occupants continue moving at the same pace the vehicle was traveling at when it stopped if it unexpectedly stops or crashes. To stop the driver and other passengers from exiting the vehicle or contacting the interiors of the vehicle, seatbelts apply an equal and opposite force to them. Due to their crucial function in occupant safety, seatbelts are regarded as the main restraint devices.

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3 0

2 years ago

I really need help with the graphs

nata0808 [166]

Answer:

t = 2s

Explanation:

When you're looking for instantaneous portions of a graph, of any sort really, it means you're observing a rate at a single point in time [or possibly some other variable]. It's sorta like a snapshot of a rate as opposed to an average rate over an interval. After choosing this rate we'll typically draw a straight, tangent line through it to indicate it's slope. (Tangent lines are just lines that only touch a single point on a graph or shape.)

Another thing to take note of are the values of the graph's major axes. The "y-axis" corresponds to velocity in meters per second, while the "x-axis" corresponds to time in seconds. Normally when relating the two we put "y" over the "x" and say that at any point there are "y[units]" per "x[units]". Though with instantaneous rates, we say the value of "x" is "1"; for reasons I can try to further explain later if you'd like.

With the above information in mind we can turn our attention to your graph. You're told to find the point on this graph where the instantaneous rate of acceleration is -2 m/s². The only place where the graph reflects an instantaneous rate of -2m/s² is at t = 2s. At t = 2, the rate comes out to (2[m/s]/1s), which simplifies to 2m/s². If you then draw the tangent line through the point, you'll find that the line is decreasing (going down from left to right) which means that the instantaneous rate is negative.

So at t = 2s, we have an instantaneous acceleration of -2m/s².

3 0

3 years ago

For a freely falling object weighing 3 kg : A. what is the object's velocity 2 s after it's release. B. What is the kinetic ener

Fed [463]

A) 19.6 m/s (downward)

B) 576 J

C) 19.6 m

D) Velocity: not affected, kinetic energy: doubles, distance: not affected

Explanation:

An object in free fall is acted upon one force only, which is the force of gravity.

Therefore, the motion of an object in free fall is a uniformly accelerated motion (constant acceleration). Therefore, we can find its velocity by applying the following suvat equation:

$v=u+at$

where:

v is the velocity at time t

u is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration due to gravity

For the object in this problem, taking downward as positive direction, we have:

$u=0$ (the object starts from rest)

$a=9.8 m/s^2$

Therefore, the velocity after

t = 2 s

is:

$v=0+(9.8)(2)=19.6 m/s$ (downward)

The kinetic energy of an object is the energy possessed by the object due to its motion.

It can be calculated using the equation:

$KE=\frac{1}{2}mv^2$

where

m is the mass of the object

v is the speed of the object

For the object in the problem, at t = 2 s, we have:

m = 3 kg (mass of the object)

v = 19.6 m/s (speed of the object)

Therefore, its kinetic energy is:

$KE=\frac{1}{2}(3)(19.6)^2=576 J$

In order to find how far the object has fallen, we can use another suvat equation for uniformly accelerated motion:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

For the object in free fall in this problem, we have:

u = 0 (it starts from rest)

$a=g=9.8 m/s^2$ (acceleration of gravity)

t = 2 s (time)

Therefore, the distance covered is

$s=0+\frac{1}{2}(9.8)(2)^2=19.6 m$

Here the mass of the object has been doubled, so now it is

M = 6 kg

For part A) (final velocity of the object), we notice that the equation that we use to find the velocity does not depend at all on the mass of the object. This means that the value of the final velocity is not affected.

For part B) (kinetic energy), we notice that the kinetic energy depends on the mass, so in this case this value has changed.

The new kinetic energy is

$KE'=\frac{1}{2}Mv^2$

where

M = 6 kg is the new mass

v = 19.6 m/s is the speed

Substituting,

$KE'=\frac{1}{2}(6)(19.6)^2=1152 J$

And we see that this value is twice the value calculated in part A: so, the kinetic energy has doubled.

Finally, for part c) (distance covered), we see that its equation does not depend on the mass, therefore this value is not affected.

5 0

3 years ago

What is the speed of light in (a) crown glass n= 1.52, (b) Lucite n = 1.51, and (c) ethyl alcohol n = 1.36?

mote1985 [20]

Answer:

$(a)\\1.97\times 10^8 m/s\\(b)\\1.99\times 10^8 m/s \\(c)\\2.21 \times 10^8 m/s$

Explanation:

According to the definition of refractive index, the refractive index of the material is defined as the ratio of speed of light in vacuum to the speed of light in medium.

(a) refractive index, n = 1.52

$n=\frac {c}{v}\\\\1.52 = \frac{3\times 10^8}{v}\\\\v = 1.97\times 10^8 m/s$

(b) refractive index, n = 1.51

$n=\frac {c}{v}\\\\1.51 = \frac{3\times 10^8}{v}\\\\v = 1.99\times 10^8 m/s$

$n=\frac {c}{v}\\\\1.36 = \frac{3\times 10^8}{v}\\\\v = 2.21\times 10^8 m/s$

4 0

3 years ago