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Ymorist [56]
2 years ago
5

Why are the magnetic fields of superconducting magnets often stronger than those of conventional magnets?

Physics
1 answer:
g100num [7]2 years ago
3 0

The superconducting magnets are able to generate powerful magnetic fields because they have no electrical resistance.

To find the answer, we have to know more about the superconducting magnets.

<h3>What is superconducting magnet?</h3>
  • An example of an electromagnet is a superconducting magnet.
  • They are constructed from coils of superconducting wire and must be used while being chilled to cryogenic temperatures.
  • Because the wire encircling the magnet has no electrical resistance when it is in its superconducting condition, they may produce powerful magnetic fields.
  • Because of this, the magnet can conduct far greater electrical currents than the typical electromagnet.

Thus, we can conclude that, the superconducting magnets are able to generate powerful magnetic fields because they have no electrical resistance.

Learn more about the superconducting magnets here:

brainly.com/question/1476682

#SPJ4

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An archer shoots an arrow with a velocity of 45.0m/s at an angle of 50.0degrees with the horizontal.An assistant standing on the
garri49 [273]

Answer:

a) u = 30.29 m/s

b) t = 2.09 s

Explanation:

given,

velocity = 45 m/s

angle (θ) = 50°

horizontal velocity = 45 cos 50°

time taken to reach 150 m.

times = \dfrac{150}{45 cos 50^0}

t  =  5.19 s

a) height of arrow

s = u t +\dfrac{1}{2}gt^2

s = v sin \theta \times t+\dfrac{1}{2}gt^2

s = 45 sin 50^0 \times 5.19 -\dfrac{1}{2}\times 9.81\times 5.19^2

s = 46.78 m

v² - u² = 2 g s

u² = 2 × 9.81 × 46.78

u = 30.29 m/s

b) time taken by the apple = \dfrac{u}{g}=\dfrac{30.29}{9.81}

                                             = 3.09 s

time after which it has to be thrown = 5.19-3.09 = 2.1 s

5 0
3 years ago
At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81m/s2 . A watermelon has a weight of 58.0N at the sur
kvasek [131]

Answer: A) mass on earth surface = 5.91kg

B) mass on surface of jupiter = 5.91kg

C) weight on surface of jupiter = 10.697N

Explanation:

The relationship between weight (W), mass (m) and acceleration due gravity (g) is given below

W=mg

From the question, g= 9.8m/s² and weight on the surface on the earth is 58N

A) The mass of watermelon on earth is

m = 58/ 9.8 = 5.91kg

B) the mass of the watermelon on jupiter is 5.91kg.

You will notice this is the same as the mass of watermelon on earth and that is so because mass is a scalar quantity that does not depends on the distance away from the center of the earth (unlike weight which is a vector) thus making it constant all through any location.

C) mass of watermelon is 5.91kg, g=9.8m/s² weight of watermelon on jupiter is given below as

W = mg

W = 5.91 x 9.8

= 10.697N.

6 0
3 years ago
Stars are formed in which of the following?
MAXImum [283]

    Stars are formed in <u>nebulas</u>, interstellar clouds of dust and gas.

6 0
3 years ago
Over a short interval the coordinate of a car in the meters isgiven by x(t) = 27t - 4.0 t3 where time t is in seconds,at the end
wariber [46]

Answer:

5. -24 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

mathematically,

a = dv/dt ............................ Equation 1

Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.

But

v = dx(t)/dt

Where,

x(t) = 27t-4.0t³...................... Equation 2

Therefore, differentiating equation 2 with respect to time.

v = dx(t)/dt = 27-12t²............. Equation 3.

Also differentiating equation 3 with respect to time,

a = dv/dt = -24t

a = -24t .................... Equation 4

from the question,

At the end of 1.0 s,

a = -24(1)

a = -24 m/s².

Thus the acceleration = -24 m/s²

The right option is 5. -24 m/s²

4 0
3 years ago
Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh
puteri [66]

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

F=kx  (1)  

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

F=(95.5N/m)(0.200m)=19.1N

Hence, the force exterted on the block is 19.1 N

 

8 0
3 years ago
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