3 years ago

A 4Kg rock is rolling 10m/s find it’s kinetic energy

Chemistry

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

KE=.5mv^2
M=mass
v=velocity
.5(4)(100)=200
That should be the answer.

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2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

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$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

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at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

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